- #1
Pindrought
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I'd love it if someone could verify whether or not I did this problem correctly.
A stained-glass window is a disc of radius 2 (graph r=2) with a rose inside (graph of r=2sin(2theta) ). The rose is red glass, and the rest is blue glass. Find the total area of the blue glass.
So I set 2=2sin(2theta) to find where they intersect and found that at theta = pi/4 there is an intersection, so I set my bounds to be from 0 to pi/4 to find an eighth section of the total area of the blue glass.
My integral looks like so
View attachment 2174
View attachment 2175
Did I do this right?
Thanks a lot for taking the time to read
A stained-glass window is a disc of radius 2 (graph r=2) with a rose inside (graph of r=2sin(2theta) ). The rose is red glass, and the rest is blue glass. Find the total area of the blue glass.
So I set 2=2sin(2theta) to find where they intersect and found that at theta = pi/4 there is an intersection, so I set my bounds to be from 0 to pi/4 to find an eighth section of the total area of the blue glass.
My integral looks like so
View attachment 2174
View attachment 2175
Did I do this right?
Thanks a lot for taking the time to read