- #1
squintyeyes
- 45
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A mass is placed on a frictionless incline and attached to a pulley by a light string. The situation is sketched below.
Rotation Test Figure 2
The incline angle, theta, is 50.0°, the mass is 4.00 kg, the moment of inertia of the pulley is 0.800 kgm2 and the radius of the pulley is 0.105 m. The mass is released from rest.
(a) What is the magnitude of the acceleration of the mass?
_____m/s2
(b) What is the magnitude of the angular acceleration of the pulley?
______rad/s2
(c) What is the tension in the string?
______ N
For part a I put down 0.438 but it got marked wrong
T= Tension
Force from weight going down the ramp= mgsinθ
a = linear acceleration
mgsinθ-T=ma
Iα=T*r
α= -a/r
T= -Iα/r = -Ia/r2
substitute the value of T
mgsinθ+Ia/r2=ma
mgsinθ=a(m-I/r2)
a= mgsinθ/(m-I/r2)= - 0.43798 m/s
I put 0.43798 because it asked for the magnitude
2)α = a/r = -4.076 rad/s
So it should be 4.076 because asked for magnitude
3)T=Ia/r2= 31.055 N
Rotation Test Figure 2
The incline angle, theta, is 50.0°, the mass is 4.00 kg, the moment of inertia of the pulley is 0.800 kgm2 and the radius of the pulley is 0.105 m. The mass is released from rest.
(a) What is the magnitude of the acceleration of the mass?
_____m/s2
(b) What is the magnitude of the angular acceleration of the pulley?
______rad/s2
(c) What is the tension in the string?
______ N
For part a I put down 0.438 but it got marked wrong
T= Tension
Force from weight going down the ramp= mgsinθ
a = linear acceleration
mgsinθ-T=ma
Iα=T*r
α= -a/r
T= -Iα/r = -Ia/r2
substitute the value of T
mgsinθ+Ia/r2=ma
mgsinθ=a(m-I/r2)
a= mgsinθ/(m-I/r2)= - 0.43798 m/s
I put 0.43798 because it asked for the magnitude
2)α = a/r = -4.076 rad/s
So it should be 4.076 because asked for magnitude
3)T=Ia/r2= 31.055 N