- #1
raconteur
- 2
- 0
Rotational Equilibrium and Dynamics - :)
I'm totally stumped!
---------------------
A skater spins with an angular speed of 12.0 rad/s with his arms outstretched. He lowers his arms, decreasing his moment of inertia from 41 kg·m² to 36 kg·m²
Calculate his initial and final rotational kinetic energy.
----------------------
Is the formula KE=1/2·I·ω² ?
ω=angular speed.. so ω=12.0 rad/s
so then how would i get I (inertia) ?
and how would i find out initial and final ?
---------------------
i just need some help
I'm totally stumped!
---------------------
A skater spins with an angular speed of 12.0 rad/s with his arms outstretched. He lowers his arms, decreasing his moment of inertia from 41 kg·m² to 36 kg·m²
Calculate his initial and final rotational kinetic energy.
----------------------
Is the formula KE=1/2·I·ω² ?
ω=angular speed.. so ω=12.0 rad/s
so then how would i get I (inertia) ?
and how would i find out initial and final ?
---------------------
i just need some help
Last edited: