Rotational Inertia of Pulley, Integration Help

In summary, the pulley with a rotational inertia of 1.5 10-3 kg·m2 and radius of 21 cm is acted on by a force that varies with time (F = 0.50t + 0.30t^{2}). At t = 10.0 s, its angular acceleration is 4900 rad/s2 and its angular velocity is 140 rad/s. To determine the angular velocity, an integral must be taken of the angular acceleration, with a constant of integration of 0 since the pulley was initially at rest.
  • #1
rmunoz
30
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Homework Statement



A pulley, with a rotational inertia of 1.5 10-3 kg·m2 about its axle and a radius of 21 cm, is acted on by a force applied tangentially at its rim. The force magnitude varies in time as F = 0.50t + 0.30t[tex]^{2}[/tex], where F is in Newtons and t in seconds. The pulley is initially at rest.

(a) At t = 10.0 s what is its angular acceleration?
rad/s2


(b) At t = 10.0 s what is its angular velocity?
rad/s




Homework Equations


Tnet=I[tex]\alpha[/tex]

f=.50t + .30t[tex]^{2}[/tex]

The Attempt at a Solution


I allready got the acceleration for the pulley. It turned out to be 4900 rad/sec. But now i assume because the amount of force is reliant on the time (in other words, is accelerating at a non-constant rate), some integration will be needed. The problem for me is, i have only the vaguest idea of how to actually integrate. Would anyone mind helping me with this problem if it does in fact require integration, by showing me the exact steps? And if that is not the case, perhaps point me in the right direction?
 

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  • #2
rmunoz said:

Homework Statement



A pulley, with a rotational inertia of 1.5 10-3 kg·m2 about its axle and a radius of 21 cm, is acted on by a force applied tangentially at its rim. The force magnitude varies in time as F = 0.50t + 0.30t[tex]^{2}[/tex], where F is in Newtons and t in seconds. The pulley is initially at rest.

(a) At t = 10.0 s what is its angular acceleration?
rad/s2

(b) At t = 10.0 s what is its angular velocity?
rad/s


Homework Equations


Tnet=I[tex]\alpha[/tex]

f=.50t + .30t[tex]^{2}[/tex]

The Attempt at a Solution


I allready got the acceleration for the pulley. It turned out to be 4900 rad/sec. But now i assume because the amount of force is reliant on the time (in other words, is accelerating at a non-constant rate), some integration will be needed. The problem for me is, i have only the vaguest idea of how to actually integrate. Would anyone mind helping me with this problem if it does in fact require integration, by showing me the exact steps? And if that is not the case, perhaps point me in the right direction?

You are correct. You will need to do an integral to determine the angular velocity.

You have already evaluated the a(t) at 10 sec to determine a|10 from

|a(t)| = |r|*|F(t)|/I = 140*|.5*t + .3*t2|

Since a(t) = dω/dt

then ω|10 = ∫a(t)*dt

or

ω|10 = 140*∫(.5t+.3t2)*dt = 140*(.25*t2 +.1*t3 + c) evaluated from 0 to 10.

Since you are told it was at rest at t=0, then the constant of integration c = 0.
 
  • #3
Awesome, thank you for the walkthrough, that was incredibly helpful
 

FAQ: Rotational Inertia of Pulley, Integration Help

1. What is rotational inertia?

Rotational inertia, also known as moment of inertia, is a measure of an object's resistance to changes in its rotational motion. It is affected by an object's mass and its distribution around the axis of rotation.

2. How is rotational inertia calculated?

The rotational inertia of a pulley can be calculated by the formula I = mr2, where I is the moment of inertia, m is the mass of the pulley, and r is the radius of the pulley.

3. How does the rotational inertia of a pulley affect its motion?

The higher the rotational inertia of a pulley, the more difficult it is to change its rotational motion. This means that a pulley with a higher rotational inertia will require more torque to accelerate or decelerate.

4. Can the rotational inertia of a pulley be changed?

Yes, the rotational inertia of a pulley can be changed by altering its mass or the distribution of its mass. For example, adding weight to the outer edge of a pulley will increase its rotational inertia.

5. How is integration used in determining the rotational inertia of a pulley?

Integration is used to calculate the moment of inertia of a pulley by considering infinitesimally small elements of mass and summing them up. This involves breaking down the pulley into smaller parts and using calculus to integrate their contributions to the overall moment of inertia.

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