Rotational Kinetic Energy -> Lightning Speed Running?

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The discussion revolves around calculating the speed one could achieve by converting the rotational kinetic energy of a solid cylindrical flywheel into linear motion. The flywheel has a mass of 200 kg and a radius of 0.8 m, rotating at 15,000 revolutions per minute, resulting in a calculated rotational kinetic energy of approximately 7.9 x 10^7 J. When equating this energy to kinetic energy for a person weighing 65 kg, the resulting speed is calculated to be around 1600 m/s, which raises concerns about feasibility. Participants note that while the calculations are mathematically correct, the practical implications highlight that such speeds and the ability to carry a 200 kg flywheel are unrealistic. The discussion emphasizes the significant energy storage capabilities of large flywheels and the confusion surrounding the application of energy conversion in this context.
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Homework Statement



Suppose a solid cylindrical flywheel has a mass of 200 kg and a radius of 0.8 m and rotates at a rate of 15,000 revolutions per minute. If you were able to convert all of its rotational kinetic energy into making you run, how fast would you be going? (Assume your mass is about 65 kg).

Homework Equations



Conversion from revolutions to rad:
1 rev/s = 2*pi*rad/s

Moment of inertia of solid cylinder:
I = (1/2)MR^2

Rotational kinetic energy of a rotating object:
Krot = (1/2)Iw^2

Kinetic energy:
K = (1/2)mv^2

The Attempt at a Solution



M = 200 kg is mass of solid cylindrical flywheel
m = 65 kg is my mass
R = 0.8m
w = 15000 rev/min = 250 rev/s = 500*pi*rad/s

Find moment of inertia of solid cylindrical flywheel:
I = (1/2)MR^2
I = (1/2)(200 kg)(0.8)^2
I = 64 kg*m

Find rotational kinetic energy of solid cylindrical flywheel:
Krot = (1/2)Iw^2
Krot = (1/2)(64 kg*m)(500*pi*rad/s)^2
Krot = 7.9 * 10^7 J

If Krot = K, then solve for v:
Krot = K = 7.9 * 10^7 J
K = (1/2)mv^2
v = sqrroot[ (2K) / m]
v = sqrroot[ (2*7.9*10^7 J) / 65 kg ]
v = 1559 = 1600 m/s

Can I set Krot = K like that? Is my approach to this problem correct? Thanks a lot for the help!
EDIT: The velocity figure looks weird...Nobody can run that fast... Where did I make a mistake?
 
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Or do I find v with v = rw? (but that wouldn't relate to energy? I'm terribly confused)
 
That is the correct way to do it ( haven't checked arithmateic)
Nobody can run that fast, but they also can't carry a 200kg flywheel running spinning at 250Hz! Large flywheels store a lot of energy - and can dump it very quickly.
 
Thanks for your help!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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