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1.)
A uniform rod of mass 0.93 kg is 17 m long.
The rod is pivoted about a horizontal, fric-
tionless pin at the end of a thin extension (of
negligible mass) a distance 17 m from the cen-
ter of mass of the rod. Initially the rod makes
an angle of 70 degrees with the horizontal. The rod
is released from rest at an angle of 70 degrees with
the horizontal.
The acceleration of gravity is 9.8 m/s^2.
Hint: The moment of inertia of the rod
about its center-of-mass is 1/12 ML^2.
What is the angular speed of the rod at
the instant the rod is in a horizontal position?
Answer in units of rad/s.
MgL/2 = .5(1/12ML^2)w^2
This works out to be:
w = sqrt(12g/L)
w = 2.630142 ?
But the answer is wrong?? why?!
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2.
Two pulley wheels, or respective radii R1 =
0.34 m and R2 = 1.5 m are mounted rigidly
on a common axle and clamped together. The
combined moment of inertia of the two wheels
is I + 4.5 kg*m^2.
Mass m1 = 18 kg is attached to a cord
wrapped around the first wheel, and another
mass m2 = 5.9 kg is attached to another cord
wrapped around the second wheel.
The acceleration of gravity is 9.8 m/s^2 :
Find the angular acceleration of the system.
Take clockwise direction as positive. Answer
in units of rad/s^2.
I = .5MR^2
I1= .5(18)(.34)^2
I2= .5(5.9)(1.5)^2
I = I1 +I2 + 4.5 = 12.1779
Acceleration= [(m2gR2)-(m1gR1)]/[I+(m1r1^2)+(m2r2^2)]
= .971689752 ??
This is wrong as well, WHY??!?
Please help. All help is appreciated.