Rotational motion, moment of inertia yoyo problem. PLEASE HELP

In summary: Yes, that is correct. Make sure you use the correct expressions for rotational and translational kinetic energy.In summary, the conversation discusses the use of conservation of energy to calculate the linear speed of a yoyo when it reaches the end of its string and the fraction of its rotational energy. The equations used include moment of inertia, linear and angular velocity, and kinetic energy. The correct approach is to use the conservation of energy equation and solve for the angular velocity, then use this value to determine the linear speed and the fraction of rotational energy.
  • #1
0338jw
42
0

Homework Statement



A yoyo is made of two solid cylindrical disks each of mass .050kg and diameter .075m joined by a concentric thin solid cylindrical hub of mass .0050kg and diameter .010m. use conservation of energy to calculate the linear speed of the yoyo when it reaches the end of its 1 m long string, if it is released at rest. b. What fraction of it's rotational energy is rotational?

Homework Equations


I=1/2 MR^2
Vt=r*omega
KErot= 1/2 I W^2
KEtrans=1/2MV^2
Wnc= deltaKE + deltaPE

The Attempt at a Solution


I have calculated the moment of intertia for the disks and hub and have aded them together. I'm not sure where exactly to go from here, so I would love to know where to go next. Would I use the hub radius and 2pi radians to determine the angular velocity? Do I use potential energy from the work equation? Please point me in the right direction!
 
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  • #2
0338jw said:

Homework Statement



A yoyo is made of two solid cylindrical disks each of mass .050kg and diameter .075m joined by a concentric thin solid cylindrical hub of mass .0050kg and diameter .010m. use conservation of energy to calculate the linear speed of the yoyo when it reaches the end of its 1 m long string, if it is released at rest. b. What fraction of it's rotational energy is rotational?

Homework Equations


I=1/2 MR^2
Vt=r*omega
KErot= 1/2 I W^2
KEtrans=1/2MV^2
Wnc= deltaKE + deltaPE

The Attempt at a Solution


I have calculated the moment of intertia for the disks and hub and have aded them together. I'm not sure where exactly to go from here, so I would love to know where to go next. Would I use the hub radius and 2pi radians to determine the angular velocity? Do I use potential energy from the work equation? Please point me in the right direction!
You in fact need to do both. Can you write an expression for the conservation of energy in this case?
 
  • #3
mgh=-1/2mv^2? Is the L in L=Iw equal to the radius of the string? I think I'm not seeing something here. what would I need to find first in order to find the angular velocity so I can determine the tangential speed at which the yoyo is travelling. Are we assuming the yoyo spins as it would in real life, or simply translating downward?
 
  • #4
0338jw said:
mgh=-1/2mv^2? Is the L in L=Iw equal to the radius of the string? I think I'm not seeing something here. what would I need to find first in order to find the angular velocity so I can determine the tangential speed at which the yoyo is travelling. Are we assuming the yoyo spins as it would in real life, or simply translating downward?
You've hit the nail on the head in your final sentence: the yoyo will not only translate, but will also rotate. Therefore, the potential energy isn't just transferred to linear kinetic energy, some must also be transferred to rotational kinetic energy.
 
  • #5
I've added together the total mass to get .105kg. I plugged this into mgh=/.5mv^2 and solved for V where i got 1.04m/s. I plugged this back into V=R*w where i used the radius of the hub to solve for angular velocity and I got 208 rad/s. Is this correct or should I have used the speed and plugged that back into the kinetic and rotational energy conservation equation and solve for w. I'm not sure how to describe the rotation of the yoyo, and I don't need it spelled out for me but I'd sure like some help with my questions. Thanks!
EDIT: when i plug the velocity back into the conservation of energy with translational and rotational and solve for w i get 166.07rad/s. Which is the correct value?
 
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  • #6
my partner is not helping much, am I on the right track?
 
  • #7
0338jw said:
I've added together the total mass to get .105kg. I plugged this into mgh=/.5mv^2 and solved for V where i got 1.04m/s. I plugged this back into V=R*w where i used the radius of the hub to solve for angular velocity and I got 208 rad/s. Is this correct or should I have used the speed and plugged that back into the kinetic and rotational energy conservation equation and solve for w. I'm not sure how to describe the rotation of the yoyo, and I don't need it spelled out for me but I'd sure like some help with my questions. Thanks!
EDIT: when i plug the velocity back into the conservation of energy with translational and rotational and solve for w i get 166.07rad/s. Which is the correct value?
Did you read my previous post? Your equation for conservation of energy is not correct, you have not taken into account the rotational kinetic energy of the yoyo.
 
  • #8
When I recalculated omega I used MGH= 1/2(total inertia)w^2 + 1/2mv^2 but I just realized i used the wrong speed from before.. Do i have the correct equation listed, however? For this equation would I substitute in omega as V/R and solve for V, if so which radius would I use, the central hub? Sorry if I'm not getting it
 
  • #9
0338jw said:
When I recalculated omega I used MGH= 1/2(total inertia)w^2 + 1/2mv^2 but I just realized i used the wrong speed from before.. Do i have the correct equation listed, however?
Much better :approve:.
0338jw said:
For this equation would I substitute in omega as V/R and solve for V, if so which radius would I use, the central hub? Sorry if I'm not getting it
Yes, since the string is wound around the central hub the linear velocity of the yoyo will be the velocity of a point on the circumference of the hub.
 
  • #10
I recalculated for speed and have 2.64m/s. From here do I plug this back into the conservation of rotational and translational energy and solve for W, and take the ratios of the KE?
 
  • #11
0338jw said:
I recalculated for speed and have 2.64m/s. From here do I plug this back into the conservation of rotational and translational energy and solve for W, and take the ratios of the KE?
There is no need to solve the conservation of energy equation again, there is a much easier method to find the angular velocity, how does w relate to v?

The question only asks you for the fraction of energy which is rotational, that is the rotational kinetic energy divided by the total energy, there is no need to calculate the linear kinetic energy.
 
  • #12
I see that v=R*w, but I remember the instructor telling us to use the radius of the string. If I do this then Vt=w. Would this be correct?
 
  • #13
0338jw said:
I see that v=R*w, but I remember the instructor telling us to use the radius of the string. If I do this then Vt=w. Would this be correct?
Radius of the string?
 
  • #14
Yeah, I wrote what he wrote down on the board, as he sort of explained it vaguely to the class. Should I use the radius of the hub? When I do use the radius of the hub I get 528 rad/s. Can anyone verify the linear speed I have is correct for the first part?
 
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FAQ: Rotational motion, moment of inertia yoyo problem. PLEASE HELP

1. What is rotational motion?

Rotational motion is the movement of an object around an axis or center point. This type of motion is circular and can be observed in objects such as spinning tops, wheels, and planets orbiting around their respective stars.

2. What is moment of inertia?

Moment of inertia is a measure of an object's resistance to rotational motion. It is similar to mass in linear motion, but instead of measuring an object's resistance to linear motion, it measures its resistance to rotational motion. The moment of inertia depends on the object's mass, shape, and how the mass is distributed around the axis of rotation.

3. How is the moment of inertia calculated for a yoyo?

The moment of inertia for a yoyo can be calculated by using the formula I = mr^2, where I is the moment of inertia, m is the mass of the yoyo, and r is the radius of the yoyo. This formula assumes that the mass of the yoyo is evenly distributed around the axis of rotation.

4. Why is the moment of inertia important in rotational motion?

The moment of inertia is important in rotational motion because it determines how quickly an object can rotate or how much torque is needed to make an object rotate at a certain speed. It also plays a role in an object's stability and its ability to maintain its rotational motion.

5. What is the yoyo problem in rotational motion?

The yoyo problem in rotational motion refers to the challenge of calculating the moment of inertia for a yoyo that has a string wrapped around its axle. This problem requires a more complex calculation, as the mass of the yoyo is not evenly distributed around the axis of rotation. It also involves considering the tension of the string and how it affects the rotational motion of the yoyo.

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