- #1
Elysian
- 33
- 0
Homework Statement
A 4 kg block, 10m above the ground is attached to a long cord which is wrapped around a 1050 g iron disc of radius 40 cm. The system is originally at rest, afterwards the block is let go and allowed to fall. From the time the block is let go to when the block crashes with the ground, calculate the speed of the block as it hits the ground
the number of revolutions the disc makes
Homework Equations
energy equations
The Attempt at a Solution
For the linear speed as it hits the ground i used
mgh = .5m1v2 + .5Iω2
Where I = 1.050*.42*.5
m1 is the mass of the disc + the block, so 1.050+5kg = 5.050 kg
I replaced ω with v/r, to have the equation
mgh = .5mv2 + .5I(v/r)2
Is this correct?
For the revolutions, I would probably use
θ = ωt + .5αt2, where t = (ωf - ωi)/α
is this part correct?
Thanks
Last edited: