- #1
shivajikobardan
- 674
- 54
Say p=5, q=11
z=(p-1)*(q-1)
=40
d relatively prime to z, so d=27
de mod z=1
27e mod 40=1
e=3
$C=M^e mod \; n$
For d, M=4
C=$4^3 mod 55$
Am I right here?
z=(p-1)*(q-1)
=40
d relatively prime to z, so d=27
de mod z=1
27e mod 40=1
e=3
$C=M^e mod \; n$
For d, M=4
C=$4^3 mod 55$
Am I right here?