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Mech-Master
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An object of mass m falls from rest at a point near the Earth's surface. If the air resistance is proportional to the velocity v^2, the differential equation for the velocity as a function of time is given by:
m*dv/dt = mg - cv^2
a) Derive the exact solution
done this part, and i got v = sqrt(m*g/c)*tanh(t*sqrt(g*c/m))
b) For the given paraments g = 9.81 m/s^2. m = 68.1 kg and c = 1.5 kg/m. plot the exact solution and the numerical solution v(t) obtained from the 4th order predictor-corrector runge kutta methods using an interval of dt = 0.25 seconds in the domain of 0<t<6
i'm having trouble coding the runge kutta method with all the k1, k2, k3 and k4.. I really need help with this.
Thanks
m*dv/dt = mg - cv^2
a) Derive the exact solution
done this part, and i got v = sqrt(m*g/c)*tanh(t*sqrt(g*c/m))
b) For the given paraments g = 9.81 m/s^2. m = 68.1 kg and c = 1.5 kg/m. plot the exact solution and the numerical solution v(t) obtained from the 4th order predictor-corrector runge kutta methods using an interval of dt = 0.25 seconds in the domain of 0<t<6
i'm having trouble coding the runge kutta method with all the k1, k2, k3 and k4.. I really need help with this.
Thanks