S there a way to calculate this using the thermodynamic identity?

The conversation discusses calculating the increase in entropy of a liter of air as it is heated at constant pressure until it doubles in volume. The individual is seeking a way to calculate this without using the Sackur Tetrode equation and considers using the thermodynamic identity. Another formula is suggested, but the individual is unsure of its accuracy. In summary, the conversation discusses calculating the increase in entropy of air as it is heated at constant pressure, with one person seeking a method that does not involve the Sackur Tetrode equation.
  • #1
Shaybay92
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Homework Statement


A liter of air, initially at room temperature and atmospheric pressure, is heated at constant pressure until it doubles in volume. Calculate the increase in its entropy during this process.

Is there a way to calculate this using the thermodynamic identity (ie. without the Sackur Tetrode equation??) I was trying to use this formula, setting dV = V_initial... Any ideas?

dS = (dS/dU)dU + (dS/dV)dV
 
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  • #2
Shaybay92 said:

Homework Statement


A liter of air, initially at room temperature and atmospheric pressure, is heated at constant pressure until it doubles in volume. Calculate the increase in its entropy during this process.

Is there a way to calculate this using the thermodynamic identity (ie. without the Sackur Tetrode equation??) I was trying to use this formula, setting dV = V_initial... Any ideas?

dS = (dS/dU)dU + (dS/dV)dV
What is the matter with:

[tex]\Delta S = \int dQ_{rev}/T = nC_p\ln(T_f/T_i) ?[/tex]

AM
 

FAQ: S there a way to calculate this using the thermodynamic identity?

What is the definition of entropy for an ideal gas?

The entropy of an ideal gas is a measure of the disorder or randomness of the particles in the gas. It is a thermodynamic quantity that increases with increasing disorder.

How is entropy related to the temperature of an ideal gas?

In an ideal gas, the entropy is directly proportional to the natural logarithm of the temperature. This means that as the temperature increases, so does the entropy.

Can the entropy of an ideal gas ever decrease?

According to the second law of thermodynamics, the entropy of an isolated system can never decrease. This means that the entropy of an ideal gas will always increase or remain constant.

What is the formula for calculating the entropy of an ideal gas?

The formula for calculating the entropy of an ideal gas is S = nRln(V/nT), where S is the entropy, n is the number of moles of gas, R is the gas constant, V is the volume, and T is the temperature.

How does the entropy of an ideal gas change during an isothermal process?

During an isothermal process, the temperature of an ideal gas remains constant. This means that the entropy will also remain constant, as it is directly proportional to the temperature.

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