- #1
geo_alchemist
- 35
- 0
Let us imagine a surface, with X and Y axes on it and Z axis normal to it.
well, the theory, (in my particular case, some article) says that S polarized light, propagating along the x-directioin possesses only electric field components, Ei, parallel to the surface (||y-direction), i.e. transversal electric waves have Ei=(0, Ey, 0), while P-polarized light has Ei=(Ex, 0, Ez).
The question:
I understand that S-polarized light, propagating along x-direction has only electric field components, Ei, parallel to the surface. Ei=(0, Ey, 0), since in case of s-polarization E is perpendicular to plane of incidence.
Also I understand that P-polarized light, propagating in the same x-direction has Ez component, since in case of P-polarization E is in the plane of incidence.
what I do not understand is, why p-polarized light has Ex component.
well, the theory, (in my particular case, some article) says that S polarized light, propagating along the x-directioin possesses only electric field components, Ei, parallel to the surface (||y-direction), i.e. transversal electric waves have Ei=(0, Ey, 0), while P-polarized light has Ei=(Ex, 0, Ez).
The question:
I understand that S-polarized light, propagating along x-direction has only electric field components, Ei, parallel to the surface. Ei=(0, Ey, 0), since in case of s-polarization E is perpendicular to plane of incidence.
Also I understand that P-polarized light, propagating in the same x-direction has Ez component, since in case of P-polarization E is in the plane of incidence.
what I do not understand is, why p-polarized light has Ex component.