- #1
karush
Gold Member
MHB
- 3,269
- 5
$\tiny{s5.t.5 Kiaser HS}$
Find domain asymptotes.
$g(x)=\dfrac{2x^2-14x+24}{x^2+6x-40}$
$\begin{array}{rll}
\textsf{factor}&=\dfrac{2(x-3)(x-4)}{(x-4)(x+10)}
=\dfrac{2(x-3)\cancel{(x-4)}}{\cancel{(x-4)}(x+10)}
=\dfrac{2(x-3)}{x+10}\\
\textsf{Domain} & -\infty<-10<\infty\\
HA \quad y&=3 \\
VA \quad x&=-10
\end{array}$
I think there is an oblique asymptote but ??
Also the OP has a hole at $x=4$ but they didn't ask for it ?
btw how come tab does not work here?
Find domain asymptotes.
$g(x)=\dfrac{2x^2-14x+24}{x^2+6x-40}$
$\begin{array}{rll}
\textsf{factor}&=\dfrac{2(x-3)(x-4)}{(x-4)(x+10)}
=\dfrac{2(x-3)\cancel{(x-4)}}{\cancel{(x-4)}(x+10)}
=\dfrac{2(x-3)}{x+10}\\
\textsf{Domain} & -\infty<-10<\infty\\
HA \quad y&=3 \\
VA \quad x&=-10
\end{array}$
I think there is an oblique asymptote but ??
Also the OP has a hole at $x=4$ but they didn't ask for it ?
btw how come tab does not work here?