- #1
JamesGoh
- 143
- 0
Say that for two mxm matrices, they have equivalent eigenvalues
If this is the case, is it safe to assume that the Jordan forms of both matrices will be the same ?
My reasoning comes from the fact that a general jordan block is represented
by the following matrix
λ 1 0 0
0 λ 1 0
0 0 λ 1
0 0 0 λ
and so on for an mxm matrix
If this is the case, is it safe to assume that the Jordan forms of both matrices will be the same ?
My reasoning comes from the fact that a general jordan block is represented
by the following matrix
λ 1 0 0
0 λ 1 0
0 0 λ 1
0 0 0 λ
and so on for an mxm matrix