- #1
Willowz
- 197
- 1
Homework Statement
For what values of a,m, and b does the function
{3 ,x=0
f(x)= {-x^2 + 3x +a ,0<x<1
{mx + b ,1<=x<=2
satisfy the hypothesis of the Mean Value Theorem of the interval [0,2].
Homework Equations
(f(b) - f(a))/(b-a) = f'(c)
The Attempt at a Solution
So, I wanted to make a point of continuity for the whole equation. So, I set the equation to x=1 in both cases and then equated them, and got;
2+a=m+b ---> a=m+b-2
Then, I found the derivative of the original equation and set x again to 1, then equated the two given that were diffable, and got;
m+b=1+a
Now I can't get any values for a,b, or m without getting:
3=0
I must be doing something wrong.