Scalar Field Theory-Vacuum Expectation Value

In summary, the student is trying to find the vacuum expectation value of a defined average field operator, squared. However, they are having trouble with the integral and end up using a gamma function to solve for the value.
  • #1
Mick83
2
0

Homework Statement


I am given an equation for a quantized, neutral scalar field expanded in creation and destruction operators, and need to find the vacuum expectation value of a defined average field operator, squared. See attached pdf.


Homework Equations


Everything is attached, but I can include more.


The Attempt at a Solution


I've solved part (a) (I think- if someone could check my work it would be appreciated), so I need some idea on how to do part (b). The question clearly asks for the expectation of the squared value, but I don't have a clue how to solve the integral in the first place, which must then be squared to find the expectation value.
 

Attachments

  • QFT_2.pdf
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  • #2
switch to spherical coordinates... put your z axis toward the direction of k i.e. measure your \theta angle from k. don't forget to use the correct integral measure...
 
  • #3
So use [tex] k_{\mu}=\bigg(\mathbf{k},\frac{i\omega}{c}\bigg),~~ x_{\mu}=(\mathbf{x},ict),~~
\mathbf{k}\cdot\mathbf{x}=k_{\mu}x_{\mu}-\omega t=k_1x_1+k_2x_2+k_3x_3-\omega t
=kr(\sin\theta \cos\phi +\sin\theta \sin\phi +\cos\theta)-\omega t [/tex]? Regardless of the θ or ∅ dependence, [tex]\int^{\infty}_0 dr~r^2~ e^{r^2/2b}~e^{ikr}[/tex] gives a horrible result, even when squared.
 
  • #4
nono that is not correct.
The kx in the power of the exponential is already only the 3-part of them. the expression is not in a "covariant" form, but the usual separate spatial and time parts.

So If you put your z axis towards the direction of k, and measure the angle \theta from there your integral will be:

[tex]\int_0^{2\pi}d\phi\int_0^{\infty}dr \, r^2 e^{-r^2/2b^2} \int_{-1}^{1}d\cos{\theta} e^{ikr\cos\theta}[/tex]The theta part can be integrated easily.

U will get the kind of integral wt you wrote:

[tex]\int_0^{\infty}dr\, r^2 e^{-r^2/2b^2}e^{\pm ikr}[/tex]

now try bringing the integrand into the form:[itex]r^2e^{-ax^2} [/itex] i.e. complete the square on the exponentials. this kind of integral can be simply expressed with gamma functions.
 
  • #5


I would first clarify the context of this question and the significance of finding the vacuum expectation value in the given scalar field theory. I would also check the work done for part (a) and ensure its accuracy before moving on to part (b).

To solve part (b), I would approach it by first understanding the integral and its physical interpretation. The integral represents the probability of finding a particular state of the system, in this case, the squared value of the average field operator. Therefore, I would use the appropriate mathematical tools and techniques to evaluate the integral and find the expectation value.

One approach could be to use the creation and destruction operators to express the average field operator in terms of these operators, and then use their properties to simplify the integral. Another approach could be to use the commutation relations of the operators to simplify the expression before integrating.

I would also consult relevant literature and resources to gain a better understanding of the concept and techniques involved in finding the vacuum expectation value in scalar field theory. Additionally, I would seek guidance from my peers and mentors to ensure the accuracy of my approach and solution.

Overall, finding the vacuum expectation value in scalar field theory is a complex task that requires a thorough understanding of the theory and its mathematical tools. I would approach it with a systematic and analytical mindset, seeking to understand the underlying principles and applying appropriate techniques to solve the problem accurately.
 

FAQ: Scalar Field Theory-Vacuum Expectation Value

1. What is Scalar Field Theory-Vacuum Expectation Value?

Scalar Field Theory-Vacuum Expectation Value is a concept in quantum field theory that describes the average value of a quantum field in its lowest energy state, known as the vacuum state. It is a fundamental concept in understanding the nature of particles and their interactions.

2. How is Scalar Field Theory-Vacuum Expectation Value calculated?

The calculation of Scalar Field Theory-Vacuum Expectation Value involves using mathematical equations and principles from quantum mechanics and field theory. It takes into account the properties of the vacuum state and the behavior of the quantum field in that state.

3. What is the significance of Scalar Field Theory-Vacuum Expectation Value?

Scalar Field Theory-Vacuum Expectation Value is significant because it helps us understand the origin of mass in particles, as described by the Higgs mechanism. It also plays a crucial role in the prediction and understanding of various physical phenomena, such as the Casimir effect and spontaneous symmetry breaking.

4. How does Scalar Field Theory-Vacuum Expectation Value relate to the Standard Model of particle physics?

Scalar Field Theory-Vacuum Expectation Value is a key component of the Standard Model, which is the most widely accepted theory explaining the fundamental interactions of particles. The Higgs boson, which is responsible for generating the vacuum expectation value, is a vital part of the Standard Model.

5. What are some practical applications of Scalar Field Theory-Vacuum Expectation Value?

Some practical applications of Scalar Field Theory-Vacuum Expectation Value include its use in the design and operation of particle accelerators, such as the Large Hadron Collider, and in the development of new technologies, such as superconductors. It also has applications in cosmology, helping us understand the evolution of the universe and the formation of structures within it.

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