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speedycaster
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Homework Statement
Question 1.
Given position vectors OA : i+2j-k and OB: 2i+j+3k in a 3D Cartesian space with origin O of the points A and B.
a) Find the scalar equation of the plane which contains A and which is perpendicular to vector AB.
b) Find the shortest distance from the point (1,-1,1) to the plane obtained in a (a)
Homework Equations
The Attempt at a Solution
Here is what i did
(a) Equation of line AB
r= (2,1,3)+ t(1,-1,4)
AP.n = 0
OP.n = OA.n
(x,y,z).(1,-1,4) = (2,1,3).(1,-1,4)
x-y+4z = 13 [equation of plane]?
(b) vector form of plane => r.(1,-1,4) = 13
line equation => r= (1,-1,1) + t(1,-1,4)
Using r=r for both equations i get t= 2/9
Substitute t=2/9 into line equation giving me (11/9, -2/9, 17/9)
I'm stuck here then for part (b)
I'm pretty weak in this chapter, couldn't seem to grab the concept here.
Homework Statement
Question 2.
Obtain the scalar equation of the plane which passes through point P(1,2,3) and contain a straight line
x(t)= 3t
y(t)= 1+t
z(t)= 2-t
t is the parameter of the line
Homework Equations
The Attempt at a Solution
Equation of the line= (0,1,2) + t(3,1,-1)
Let Q and R be the points on the line
t=0 Q=(0,1,2)
t=1 R= (3,2,1)
Therefore PQ= (-1,-1,-1) PR= (2,0,2)
PQxPR= (-2,0,-2)
Thus the equation of the plane
a(x-x1) + b(y-y1) + c(z-z1)= 0
-2(x-1) + 0 -2(z-3) = 0
-2x - 2z + 8 = 0
is this correct?
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