Schwarzchild solution and orbit precession

In summary, the discussion revolves around the precession of elliptical test-particle orbits in the highly symmetric Schwarzschild geometry of a static spacetime. The model system is isolated and spherically symmetric with only the radial coordinate being non-Euclidean. It is shown that the periodicity of r is different from that of theta, leading to non-closed orbits and precession. The direction of the precession is determined by the direction of the orbit itself. The Schwarzschild metric provides a local angular reference for this effect. Ultimately, the cause of precession is the particle's non-radial velocity vector, introducing asymmetry into an otherwise symmetric system.
  • #1
oldman
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In the Schwarzschild geometry of a static spacetime, elliptical test-particle orbits precess at a rate that (famously) agrees with observations of the inner solar system. Yet the model system considered is isolated, spherically symmetric with only the radial coordinate non-Euclidean.

I can't figure out what the axes of the ellipse precess "relative to" in this highly symmetric situation. Neither the "fixed stars" nor the CMB provide any explicit reference frame for the model. Does the analyst somehow provide an implicit reference?

Indeed I fail to see what physically causes the GR precession in such a symmetric model situation. How does the feature of orbital precession get built into the model?
 
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  • #2
oldman said:
In the Schwarzschild geometry of a static spacetime, elliptical test-particle orbits precess at a rate that (famously) agrees with observations of the inner solar system. Yet the model system considered is isolated, spherically symmetric with only the radial coordinate non-Euclidean.

I can't figure out what the axes of the ellipse precess "relative to" in this highly symmetric situation. Neither the "fixed stars" nor the CMB provide any explicit reference frame for the model. Does the analyst somehow provide an implicit reference?

Indeed I fail to see what physically causes the GR precession in such a symmetric model situation. How does the feature of orbital precession get built into the model?

Look at the effective potential formulation for orbiting bodies in GR. r and theta both vary periodically as a function of time, but the period in the variation of r is different than the period in the variation of theta in the GR formulation.

In the Newtonian case, the period of r exactly matches the period of theta, and the orbit is closed. Not so in the GR case - the fact that the perodicity of r is different from the periodicity of theta implies that the orbits are not closed, but precess.

There is a detailed reference to this in Goldstein, "Classical mechanics". Much of the discussion in Goldstein covers the effective potential approach, and in general relates to how one solves the differential equations for an orbiting body for general force laws.

There is even a discussion specifically of the precession of Mercury's perihelion in Goldstein, but the differential equations themselves is not derived there, the necessary equations are rather imported from MTW's "Gravitation". This is the same source used for the above webpage. Note that you will also find most of the same material in "Exploring Black Holes" (which is probably an easier read than MTW, which is graduate level) if you want a textbook reference. The very quick summary is that if you replace Newtonian t by GR tau, the differential equations for the orbit are formally very similar, except for an added 1/r^3 term in the GR equations. This is referred to in MTW, for example, as "the pit in the potential". It is this "pit in the potential" which causes the periodicity of r to change relative to the perodicity of theta.

Thus, it is the direction of mercury's orbit itself which determines the direction of the precession. If you reverse the orbital direction, you reverse the precession.
 
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  • #3
pervect said:
Look at the effective potential formulation for orbiting bodies in GR... Thus, it is the direction of mercury's orbit itself which determines the direction of the precession. If you reverse the orbital direction, you reverse the precession.

Yes, now I see it clearly. Thanks for the detailed help -- it's much appreciated.

As for the first part of my post:
In the Schwarzschild geometry ...somehow provide an implicit reference?
I now wish I hadn't made such a silly comment.

I've realized that describing the path of, say, Mercury as an orbit that is a precessing ellipse, while apt, is just using familiar words to describe a geodesic that is in fact not a closed path at all. I was thinking of an orbit as a path that is identically traced over and over again.
 
  • #4
oldman said:
I can't figure out what the axes of the ellipse precess "relative to" in this highly symmetric situation. Neither the "fixed stars" nor the CMB provide any explicit reference frame for the model. Does the analyst somehow provide an implicit reference?

In addition to pervect's answer, I think that the Schwarzschild metric provides a local angular reference. After all, we set up a non-rotating coordinate system with r, phi and theta as parameters. This makes it possible to have a sign for dphi/dt and dtheta/dt and hence a sign for the orbital precession.
 
  • #5
Jorrie said:
In addition to pervect's answer, I think that the Schwarzschild metric provides a local angular reference. After all, we set up a non-rotating coordinate system with r, phi and theta as parameters. This makes it possible to have a sign for dphi/dt and dtheta/dt and hence a sign for the orbital precession.
I now realize that the ultimate reason for precession is the particle's non-radial velocity vector. This introduces asymmetry into an otherwise spherically symmetric situation, making the GR geodesic an open path, in contrast to a Newtonian orbit.

Thanks, Jorrie.
 

FAQ: Schwarzchild solution and orbit precession

1. What is the Schwarzschild solution?

The Schwarzschild solution is a mathematical solution to Einstein's field equations in general relativity that describes the gravitational field outside a spherical, non-rotating mass. It is named after the German physicist Karl Schwarzschild.

2. How does the Schwarzschild solution relate to orbit precession?

The Schwarzschild solution predicts that the orbit of a test particle around a massive object, such as a star or a black hole, will precess over time due to the curvature of spacetime caused by the object's gravitational field. This is known as the Schwarzschild precession or the perihelion precession.

3. What causes the precession of orbits in the Schwarzschild solution?

The precession of orbits in the Schwarzschild solution is caused by the curvature of spacetime near a massive object. This curvature is a result of the mass of the object bending the fabric of spacetime, causing the orbiting object to follow a curved path instead of a straight line.

4. Can the Schwarzschild solution accurately predict the precession of all orbits?

No, the Schwarzschild solution is only accurate for non-rotating, spherically symmetric objects. For objects with more complex shapes or that are rotating, other solutions, such as the Kerr solution, must be used to accurately predict orbit precession.

5. Is the Schwarzschild solution important in modern science?

Yes, the Schwarzschild solution is an important tool in modern science, particularly in the study of black holes and the behavior of objects near them. It has also been used to test the predictions of general relativity and has been confirmed by numerous observations and experiments.

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