Schwarzschild Spacetime: Ellipsoidal for Moving Observers?

In summary, a spherically symmetric spacetime produced by a spherical mass looks ellipsoidal for an observer with a relative velocity compared to that body, but this is not always the case.
  • #1
center o bass
560
2
In special relativity a sphere in the rest frame for some observer looks like an ellipsoid for an observer with a relative velocity.

Can we use the same reasoning for the Schwarzschild spacetime? Namely that a spherically symmetric spacetime produced by a spherical mass look ellipsoidal for an observer with a relative velocity compared to that body?
 
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  • #2
center o bass said:
Can we use the same reasoning for the Schwarzschild spacetime?

No, because Schwarzschild spacetime itself is not a spherical object. See below.

center o bass said:
a spherically symmetric spacetime produced by a spherical mass look ellipsoidal for an observer with a relative velocity compared to that body?

Are you asking about a spherical object (like an idealized ball or an idealized planet or star) or about a spherically symmetric spacetime? They're two different things.

For a spherical object, assuming the effects of any other objects can be neglected, yes, as long as you are far enough away from it, the spacetime curvature due to the body's mass can be ignored and you can treat it as just a spherical object in flat spacetime, in which case things work the same as they do in SR.

For a spherically symmetric spacetime, you can't look at it "from the outside"; you're in it. The spherical symmetry of the spacetime is a global geometric property, which you can measure and verify regardless of your state of motion within that spacetime.
 
  • #3
As Peter noted, symmetries are invariants, that can be stated in terms if e.g. existence of different types killing vector fields. However, typically, only well chosen coordinates manifest all symmetries the sense of the metric expressed in those coordinates showing them. Thus standard inertial coordinates in flat spacetime show homogeneity and isotropy. However, Rindler coordinates (natural for a uniformly accelerating observer), show neither isotropy nor homogeneity in the metric expression. The symmetries haven't disappeared, but they are not manifest in those coordinates. Similarly, a spherically symmetric spacetime booted ultra-relativistically produces the Aichelburg-Sexl metric, which does not show spherical symmetry in coordinate expression:

http://en.wikipedia.org/wiki/Aichelburg–Sexl_ultraboost
 
  • #4
center o bass said:
In special relativity a sphere in the rest frame for some observer looks like an ellipsoid for an observer with a relative velocity.

Can we use the same reasoning for the Schwarzschild spacetime? Namely that a spherically symmetric spacetime produced by a spherical mass look ellipsoidal for an observer with a relative velocity compared to that body?

GR doesn't really have "frames". So we have to do a bit of translation work to interpret the question. It's not clear to me at the moment the best way to do this :(. My current best attempt at an interpretation is "what does the Schwarzschild geometry look like in the fermi-normal coordinates associated with a moving observer". Unfortunately this isn't an easy question to answer, while Fermi normal coordinates are conceptually useful, giving the best extended equivalent to the Newtonian idea of a frame that GR has to offer, they are hard to calculate. I would guess that a spherical shell of constant Schwarzschild time would be converted into a non-synchronized ellipsoidal shell in fermi normal coordinates, but I haven't done the calculations to attempt to show this and I'm unlikely to.

If you consider a small region around some point where the curvature effects are small enough to be neglected, you can do something much simpler than use Fermi Normal coordinates. Instead, you use the idea of a local "frame field" in the flat tangent space. This also is friendly to one's Newtonian intuition, and it's easier to calculate when you are interested in a region close enough to the observer that you don't have to account for curvature effects.
 
  • #5


Yes, the same reasoning can be applied to the Schwarzschild spacetime. In general relativity, the shape of spacetime is determined by the distribution of matter and energy. Therefore, a spherically symmetric spacetime produced by a spherical mass will appear ellipsoidal to an observer with a relative velocity compared to that mass.

This is due to the effects of time dilation and length contraction in general relativity. As an observer moves with a relative velocity compared to a massive object, their perception of time and space will be distorted, causing the shape of the spacetime to appear different.

Furthermore, in the case of a rotating black hole, the spacetime is not only distorted but also dragged along with the rotation, resulting in an even more complex shape for moving observers.

The concept of an ellipsoidal spacetime for moving observers is important in understanding the effects of gravity on the perception of time and space. It also has practical applications in fields such as astrophysics and cosmology, where the study of moving objects in curved spacetime is crucial.

In summary, the Schwarzschild spacetime can indeed appear ellipsoidal to an observer with a relative velocity, just like a sphere in special relativity. This is a fundamental aspect of general relativity that has been confirmed through various experiments and observations.
 

FAQ: Schwarzschild Spacetime: Ellipsoidal for Moving Observers?

What is Schwarzschild Spacetime?

Schwarzschild Spacetime is a mathematical model used in general relativity to describe the spacetime surrounding a non-rotating, spherically symmetric massive object, such as a black hole or a star.

What is the significance of the ellipsoidal shape in Schwarzschild Spacetime?

The ellipsoidal shape in Schwarzschild Spacetime represents the distortion of spacetime caused by the massive object. This distortion causes the paths of objects to curve, leading to phenomena such as gravitational lensing and time dilation.

How does Schwarzschild Spacetime account for the motion of observers?

Schwarzschild Spacetime accounts for the motion of observers by incorporating their motion into the mathematical equations. This results in a time-dependent ellipsoidal shape, as the distortion of spacetime changes with the observer's motion.

Can Schwarzschild Spacetime be applied to objects other than black holes and stars?

Yes, Schwarzschild Spacetime can be applied to any massive object, as long as it is non-rotating and spherically symmetric. This includes planets, asteroids, and even artificial satellites.

How does the concept of Schwarzschild Spacetime relate to our understanding of gravity?

Schwarzschild Spacetime is a key concept in general relativity, which is the modern theory of gravity. It provides a mathematical framework for understanding the effects of gravity on spacetime and has been successfully tested through various experiments and observations.

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