- #1
Dustinsfl
- 2,281
- 5
$$
\begin{cases}
x'=.05\left[y-\left(\frac{1}{3}x^3 - x\right)\right]\\
y'=-\frac{1}{.05}x
\end{cases}
$$
So this a Van de Pol equation where $\mu = .05$. It is basically a circle at the origin with radius 2. How do I find the period?
\begin{cases}
x'=.05\left[y-\left(\frac{1}{3}x^3 - x\right)\right]\\
y'=-\frac{1}{.05}x
\end{cases}
$$
So this a Van de Pol equation where $\mu = .05$. It is basically a circle at the origin with radius 2. How do I find the period?