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Illgresi
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Hi all, hopefully this is in the correct section here. Any help is really gratefully received.
1. Homework Statement
I have a coursework, one question asks us to use a 2nd order approximation of the transfer function to..."estimate the settling time (5% of the settling value of output, peak time and rise time (10%-90% of the nalvalue of response) of the closed loop system with 25% of overshoot."
Unfortunately the notes given are completely insufficient and provide no examples.
G(s) = (2360·K·s + 118000) / ((s + 160)·(s^2 - 1960))
My first thought is to simply discard the (s + 160) term, however, this would leave only (s^2 - 1960) as the denominator, and without a middle term, the function has no damping coefficient. Without a damping coefficient the system is undamped, and therefore has no settling time!
Now, I realize I can calculate the damping ratio from the overshoot provided, however, this seems like a backward method.
1. Homework Statement
I have a coursework, one question asks us to use a 2nd order approximation of the transfer function to..."estimate the settling time (5% of the settling value of output, peak time and rise time (10%-90% of the nalvalue of response) of the closed loop system with 25% of overshoot."
Unfortunately the notes given are completely insufficient and provide no examples.
Homework Equations
G(s) = (2360·K·s + 118000) / ((s + 160)·(s^2 - 1960))
The Attempt at a Solution
My first thought is to simply discard the (s + 160) term, however, this would leave only (s^2 - 1960) as the denominator, and without a middle term, the function has no damping coefficient. Without a damping coefficient the system is undamped, and therefore has no settling time!
Now, I realize I can calculate the damping ratio from the overshoot provided, however, this seems like a backward method.
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