- #1
jtruth914
- 21
- 0
Find a solution to the following second order differential equation
xy'+y=1/y^2
My Attempt:
P= y'= dy/dx
x dy/dx + y = 1/y^2
dy/dx + y/x = 1/xy^2
Integrating Factor = e^∫1/x dx = e^lnx
y e^lnx=∫ (e^lnx)(1/xy^2) dx
xy'+y=1/y^2
My Attempt:
P= y'= dy/dx
x dy/dx + y = 1/y^2
dy/dx + y/x = 1/xy^2
Integrating Factor = e^∫1/x dx = e^lnx
y e^lnx=∫ (e^lnx)(1/xy^2) dx