- #1
shamieh
- 539
- 0
Consider the second-order homogeneous linear differential equation $y'' + 4y' + Ky = 0$
Find the general solution if $K = 4$
So here is what I have:
$r^2 + 4r + 4 = 0 $
=$(r + 2)(r+2)$
$r=-2$ ?
But I thought that you can't do this because you won't be learning anything new if you have two of the same solutions. I'm not sure what to do
Find the general solution if $K = 4$
So here is what I have:
$r^2 + 4r + 4 = 0 $
=$(r + 2)(r+2)$
$r=-2$ ?
But I thought that you can't do this because you won't be learning anything new if you have two of the same solutions. I'm not sure what to do