- #1
helpinghand
- 39
- 0
Can some one help me to understand this:
I need to use the second shifting theorem to get the Laplace transform, given:
f(t) = { 4 - t2 , t < 2 ...... 1
{ 0 , t >= 2
They got this:
f(t) = (4 - t2)(1 - u(t - 2)) .... 2
I know that the second shifting theroem says that L(g(t-k)u(t-k)) = e-skG(s)
But the thing is I don't know how they get from 1 to 2, can someone please explain this?
Cheers
I need to use the second shifting theorem to get the Laplace transform, given:
f(t) = { 4 - t2 , t < 2 ...... 1
{ 0 , t >= 2
They got this:
f(t) = (4 - t2)(1 - u(t - 2)) .... 2
I know that the second shifting theroem says that L(g(t-k)u(t-k)) = e-skG(s)
But the thing is I don't know how they get from 1 to 2, can someone please explain this?
Cheers