- #1
scud0405
- 14
- 0
So, here's the problem:
[tex]\frac{dy}{dx} = \frac{8y}{5x}[/tex]
To start off, I separate the integrals, which gives me:
[tex]\frac{dy}{8y} = \frac{dy}{5x}[/tex]
After that, I integrate both sides, which gives me:
[tex]\frac{ln8y}{8} = \frac{ln5x}{5} + c [/tex]
Now, the question says that it runs through (4, 1), so that is saying that y(4) = 1, correct?
To solve for c, I just plug the 4 in where the Xs are and the 1 is where the Ys are?
EDIT: Sorry, posted in the wrong forum! Please move this thread for me :\
[tex]\frac{dy}{dx} = \frac{8y}{5x}[/tex]
To start off, I separate the integrals, which gives me:
[tex]\frac{dy}{8y} = \frac{dy}{5x}[/tex]
After that, I integrate both sides, which gives me:
[tex]\frac{ln8y}{8} = \frac{ln5x}{5} + c [/tex]
Now, the question says that it runs through (4, 1), so that is saying that y(4) = 1, correct?
To solve for c, I just plug the 4 in where the Xs are and the 1 is where the Ys are?
EDIT: Sorry, posted in the wrong forum! Please move this thread for me :\