- #1
beanryu
- 92
- 0
okay... i got this problem
sovle the separable differential equation
4x-2y(x^2+1)^(1/2)(dy/dx)=0
using the following intial condition: y(0) = -3
y^2 = ? (function of x)
I guess that means the constant is -3
so i put all the x on 1 side and all the y on one side
4x = 2y(x^2+1)^(1/2)(dy/dx)
(4x)(dx) = 2y(x^2+1)^(1/2)(dy)
(4xdx)/(x^2+1)^(1/2) = 2ydy
integral both sides I got
4(x^2+1)^(1/2) = y^2
i tried the following answers
y^2 = 4(x^2+1)^(1/2)
y^2 = 4(x^2+1)^(1/2)+9
y^2 = 4(x^2+1)^(1/2)-3
they are all wrong!
WHAT IS WRONG?! IS MY WAY OF DOING IT TATALLY WRONG?!
sovle the separable differential equation
4x-2y(x^2+1)^(1/2)(dy/dx)=0
using the following intial condition: y(0) = -3
y^2 = ? (function of x)
I guess that means the constant is -3
so i put all the x on 1 side and all the y on one side
4x = 2y(x^2+1)^(1/2)(dy/dx)
(4x)(dx) = 2y(x^2+1)^(1/2)(dy)
(4xdx)/(x^2+1)^(1/2) = 2ydy
integral both sides I got
4(x^2+1)^(1/2) = y^2
i tried the following answers
y^2 = 4(x^2+1)^(1/2)
y^2 = 4(x^2+1)^(1/2)+9
y^2 = 4(x^2+1)^(1/2)-3
they are all wrong!
WHAT IS WRONG?! IS MY WAY OF DOING IT TATALLY WRONG?!