- #1
Beez
- 32
- 0
Hi, I have just started my differential equations class. To solve the initial-value problem, 8cos^2ydx + csc^2xdy = 0 (initial condition: y(pai/12) = (pai/4) )using separable equations method, I have to change the equation to
8/csc^2dx + 1/cos^2ydy (Am I right so far?)
My problem is I don't know (or remember) how to integrate neither 8/csc^2dx nor 1/cos^2y. Am I suppose to do know how to calculate if I have finished Calculus II? I reviewed Trig. and Calculus textbooks to figure out how to calculate them but so far could not find even a similar problem.
I also have no idea how to integrate the followings:
a. x/secx dx
b. 1/cot^2x dx
c. 1/cos3y dx
d. 1/sec^3 10x dx
Any kind of help would be highly appreciated!
8/csc^2dx + 1/cos^2ydy (Am I right so far?)
My problem is I don't know (or remember) how to integrate neither 8/csc^2dx nor 1/cos^2y. Am I suppose to do know how to calculate if I have finished Calculus II? I reviewed Trig. and Calculus textbooks to figure out how to calculate them but so far could not find even a similar problem.
I also have no idea how to integrate the followings:
a. x/secx dx
b. 1/cot^2x dx
c. 1/cos3y dx
d. 1/sec^3 10x dx
Any kind of help would be highly appreciated!