SeqSum: Sum of Consecutive Ints Equal to n

[Dr.Brain]

Write a program called seqsum (source code: seqsum.c) that reads an integer n from the keyboard, and that prints all sequences of consecutive integers whose sum is equal to n. For example, if the input was 30, the program should print out
4,5,6,7,8
6,7,8,9
9,10,11

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This is the code i wrote...and it gives no errors...but after running it when i input the number 'n' and press enter..it does nothing... :(

main()
{
int i,j,k,m,n;
printf("Input number : \n");
scanf("%d" , &n);
for(i=1;i<=(n/2);i++)
{ k=0;
for(j=i;j<=(n/2+1);j++)
{ k+=j;
if(k==n)
{ for(m=i;m<=j;m++)
printf("%f \t ",m); }
printf("\n");
}
}
}

 

[NateTG]

The code tag is your friend...

main() {
   int i,j,k,m,n;
   printf("Input number : \n");
   scanf("%d" , &n);
   for(i=1;i<=(n/2);i++) {
      k=0;
      for(j=i;j<=(n/2+1);j++) {
         k+=j;
         if(k==n) {  
            for(m=i;m<=j;m++)
               printf("%f \t ",m);
         }
         printf("\n");
      }
   }
}

Just for fun, you might want to check whether scanf is returning 0.
Why are you using %f in printf when m is an integer?

 

[ravenprp]

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Your code looks mostly correct, but there are a few issues that could be causing it to not run as expected.

1. The first issue is that you are using the wrong format specifier in your printf statement. Since you are printing integers, you should use %d instead of %f.

2. Another issue is that you are using a floating-point variable (m) in your for loop instead of an integer. This could cause unexpected results and potentially an infinite loop.

3. Lastly, your code is missing a main function declaration. It should be declared as "int main()" instead of just "main()".

After making these changes, your code should run properly. Additionally, you may want to add some error handling in case the user inputs a negative number or zero, as well as a message if no sequences are found for a given number. Overall, good job on attempting to solve the problem and I hope this helps!