Set up a tridiagonal for a system of equations

In summary: Your Name]In summary, building a tridiagonal matrix for the given system of simultaneous equations involves first discretizing the equations using the explicit finite difference method. Then, rearranging the equations to form a matrix equation of the form Ax=b, where A is a tridiagonal matrix and b is a vector containing known terms. The tridiagonal matrix can be created by considering the discretized equations for each grid point and time step, with each equation contributing three terms to the diagonal, upper diagonal, and lower diagonal of the matrix. Finally, a tridiagonal solver can be used to solve for the unknown variables at each grid point and time step.
  • #1
Hypatio
151
1
I am trying to solve the system of simultaneous equations:
[tex]\frac{\partial \rho_f\phi}{\partial t}+\frac{\partial}{\partial z}(\rho_f\phi v_f)= \frac{\partial F}{\partial t}[/tex]
[tex]\frac{\partial \rho_s(1-\phi)}{\partial t}+\frac{\partial}{\partial z}(\rho_s(1-\phi) v_s)=-\frac{\partial F}{\partial t}[/tex]
and
[tex]v_f-v_s=-\frac{k}{\phi \mu}\frac{\partial P}{\partial z}[/tex]
where v_s and v_f are unknown except v_s is known at the lower boundary in z.
I will use explicit finite differences such that, I think, the discretized forms are
[tex]\rho_f^n\phi^n-\rho_f^0\phi^0+\frac{\Delta t}{\Delta z}[\rho_f^n\phi^nv_f^n-\rho_f^0\phi^0v_f^0]=F^n-F^0[/tex]
[tex]\rho_s^n(1-\phi^n)-\rho_s^0(1-\phi^0)+\frac{\Delta t}{\Delta z}[\rho_s^n(1-\phi^n)v_s^n-\rho_s^0(1-\phi^0)v_s^0]=-(F^n-F^0)[/tex]
and
[tex]v_f-v_s=-\frac{k}{\phi \mu}\frac{P_{z+1}-P_z}{\Delta z}[/tex]
where superscripts n and 0 are for new time and current time, respectively.
But I do not understand what the strategy should be for building a tridiagonal matrix with these equations. What should I be doing? How can I set this up?

More on terms: v_f and v_s are velocities, rho_f and rho_s are densities, \phi is volume of material moving at velocity v_f, F is a mass flux, and k and
\mu are constants.
 
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  • #2

Thank you for sharing your system of equations. It seems like you are working on a transport problem involving two different materials (represented by the subscripts f and s). In order to build a tridiagonal matrix for this system, you will need to first discretize the equations using the explicit finite difference method as you have done. This will result in a set of equations for each time step and grid point.

Next, you will need to rearrange the equations in order to have all the unknowns on one side and known terms on the other side. This will allow you to create a matrix equation of the form Ax=b, where A is a tridiagonal matrix, x is a vector containing the unknown variables, and b is a vector containing the known terms.

To create the tridiagonal matrix, you will need to consider the discretized equations for each grid point and time step. Each equation will contribute three terms to the diagonal, upper diagonal, and lower diagonal of the matrix. The exact values of these terms will depend on the specific discretization scheme you are using.

Once you have the matrix A, you can solve for the unknown variables using a tridiagonal solver, such as the Thomas algorithm. This will give you the values of v_f, v_s, and \phi at each grid point and time step.

I hope this helps guide you in building the tridiagonal matrix for your system of equations. If you have any further questions, please don't hesitate to ask. Good luck with your research.
 

FAQ: Set up a tridiagonal for a system of equations

1. What is a tridiagonal system of equations?

A tridiagonal system of equations is a set of linear equations where the only non-zero entries are on the main diagonal, the diagonal above, and the diagonal below. This type of system is commonly used in numerical methods for solving large systems of equations.

2. How do you set up a tridiagonal system of equations?

To set up a tridiagonal system of equations, you need to arrange the coefficients of the variables in a specific way. The first row will have the coefficient of the first variable, followed by the coefficient of the second variable in the second column, and so on. The second row will have the coefficient of the second variable in the first column, followed by the coefficient of the third variable in the second column, and so on. The rest of the rows will follow this pattern, with the main diagonal having the coefficients of the variables and the diagonals above and below having the coefficients of the variables one place to the left and right, respectively.

3. What is the purpose of setting up a tridiagonal system of equations?

The purpose of setting up a tridiagonal system of equations is to make solving a large system of linear equations more efficient. By arranging the coefficients in a specific way, we can use specialized algorithms and techniques to quickly find the solutions to the system of equations.

4. What are the advantages of using a tridiagonal system of equations?

One of the main advantages of using a tridiagonal system of equations is that it can significantly reduce the amount of time and computational resources needed to solve a large system of equations. This can be especially useful in scientific and engineering applications where solving complex equations is a common task.

5. Are there any limitations to using a tridiagonal system of equations?

While a tridiagonal system of equations can be beneficial in certain situations, it is not always the best approach. This method relies on the coefficients of the equations being arranged in a specific way, which may not always be possible. Additionally, certain types of equations may not be easily solved using this method, so it is important to carefully consider the problem at hand before deciding to use a tridiagonal system of equations.

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