Setting up limits of integration for multiple integral

In summary, the problem is trying to find the volume of a region bounded by (x-1)^2 + y^2=1, (x-1)^2+z^2=4, and -\sqrt{4-r^2} < z < \sqrt{4-r^2}. The solution is given by \int\limits_{-\pi/2}^{\pi/2}\int\limits_0^{(2\cos\theta)}\int\limits_{(-\sqrt{4-r^2})}^{(\sqrt{4-r^2})} dz\,(r\,dr)\,d\theta where
  • #1
dustbin
240
5

Homework Statement



I need to find the volume of the region bounded by

[tex] (x-1)^2 + y^2 =1 \ \ \text{and} \ \ x^2+y^2+z^2=4 \ .[/tex]
But I only need help setting up the limits of integration.

Homework Equations



The typical cylindrical change of variables.

The Attempt at a Solution



I have [itex] 0 \leq r \leq 2\cos\theta, \ -\sqrt{4-r^2} \leq z \leq \sqrt{4-r^2}, \ \text{and} \ -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}. [/itex] Then the volume is given by
[tex]
\int\limits_{-\pi/2}^{\pi/2}\int\limits_0^{(2\cos\theta)}\int\limits_{(-\sqrt{4-r^2})}^{(\sqrt{4-r^2})} dz\,(r\,dr)\,d\theta \ .
[/tex]
 
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  • #2
Pls define your cylindrical coordinate frame.
 
  • #3
Your integral is over a cylinder with center at (0, 0). The cylinder of the problem has center at (1, 0).
 
  • #4
@haruspex: Sorry, but I do not know what you mean by cylindrical coordinate frame.

@HallsofIvy: I thought that taking [itex] 0 \leq r \leq 2\cos\theta [/itex] with [itex] \theta\in(-\pi/2, \pi/2) [/itex] made it so that I would be integrating over the projection of the cylinder onto the [itex] x,y [/itex] plane as a circle of radius 1 centered at (1,0). The region is bound by [itex] \pm\sqrt{4-r^2} [/itex] on [itex] z [/itex]. Can I get some insight into how I can fix my limits of integration?
 
  • #5
dustbin said:

Homework Statement



I need to find the volume of the region bounded by

[tex] (x-1)^2 + y^2 =1 \ \ \text{and} \ \ x^2+y^2+z^2=4 \ .[/tex]
But I only need help setting up the limits of integration.

Homework Equations



The typical cylindrical change of variables.

The Attempt at a Solution



I have [itex] 0 \leq r \leq 2\cos\theta, \ -\sqrt{4-r^2} \leq z \leq \sqrt{4-r^2}, \ \text{and} \ -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}. [/itex] Then the volume is given by
[tex]
\int\limits_{-\pi/2}^{\pi/2}\int\limits_0^{(2\cos\theta)}\int\limits_{(-\sqrt{4-r^2})}^{(\sqrt{4-r^2})} dz\,(r\,dr)\,d\theta \ .
[/tex]
That integral looks fine to me.

What's your question?
 
  • #6
SammyS said:
That integral looks fine to me.

Agreed. Not clear what the fuss is about.
 

FAQ: Setting up limits of integration for multiple integral

1. What are the different types of limits of integration for multiple integrals?

There are two types of limits of integration for multiple integrals: rectangular and polar. Rectangular limits of integration are defined by two sets of numbers, representing the boundaries of the region of integration in the x and y directions. Polar limits of integration are defined by a radius and an angle, representing the boundaries of the region of integration in polar coordinates.

2. How do I determine the limits of integration for a rectangular region?

To determine the limits of integration for a rectangular region, you must first visualize the region and determine the boundaries in the x and y directions. The lower and upper limits for the x direction will be the x-coordinates of the left and right boundaries, respectively. Similarly, the lower and upper limits for the y direction will be the y-coordinates of the bottom and top boundaries, respectively.

3. How do I determine the limits of integration for a polar region?

To determine the limits of integration for a polar region, you must first visualize the region and determine the boundaries in terms of radius and angle. The lower and upper limits for the radius will be the inner and outer boundaries, respectively. The lower and upper limits for the angle will be the starting and ending angles, respectively.

4. Can the limits of integration change when converting from rectangular to polar coordinates?

Yes, the limits of integration can change when converting from rectangular to polar coordinates. This is because the boundaries of the region of integration may be different in the two coordinate systems. It is important to carefully consider and adjust the limits of integration when making this conversion.

5. How do I set up the limits of integration for a triple integral?

To set up the limits of integration for a triple integral, you must first determine the boundaries of the region of integration in three dimensions. This can be done by visualizing the region and determining the boundaries in the x, y, and z directions. The lower and upper limits for the x, y, and z directions will be the x, y, and z-coordinates of the boundaries, respectively.

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