- #1
leright
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I understand that it was Nyquist who proved that a channel of bandwidth B can transmit at a baud rate of 2B. Also, Shannon, about 10 years later showed that if a signal is sampled at a rate of at least 2B, where B is the bandwidth of the bandlimited signal, then the signal can be reconstructed from the samples. I read that Nyquist's theorem implies shannon's theorem, but I do not see how this is the case.
It is for this reason that the sampling theorem is sometimes called the 'shannon-nyquist theorem'. However, I cannot make the connection between the two theorems. The only connection I see is the '2B' part. For this reason, I don't really see why Nyquist deserves any credit for the sampling theorem...
It is for this reason that the sampling theorem is sometimes called the 'shannon-nyquist theorem'. However, I cannot make the connection between the two theorems. The only connection I see is the '2B' part. For this reason, I don't really see why Nyquist deserves any credit for the sampling theorem...