- #1
PainterGuy
- 940
- 70
Hi
I use Scientific Workplace to write down math equations and also to create documents involving mathematics and to do calculations. Although most people use it for writing science articles, I've found it extremely helpful for whatever little bit of mathematics I do.
I face a problem when I need to share my work with someone, say, on this forum. Mostly I take a screenshot of my work and share it like this. But I can imagine that it's not easy for a person who is trying to help me to correct any error in my calculations or to point out a certain fragment or equation from the screenshot. What can I do to make it little easier and convenient for others? The software can produce xHTML page too but the forum doesn't support the format. When I try to copy the latex code for the linked screenshot, I get the following which doesn't make much sense and I don't know how to put into proper latex form so it can be made work here.
Please let me know that how I can make it little easier for others. Thank you.
I use Scientific Workplace to write down math equations and also to create documents involving mathematics and to do calculations. Although most people use it for writing science articles, I've found it extremely helpful for whatever little bit of mathematics I do.
I face a problem when I need to share my work with someone, say, on this forum. Mostly I take a screenshot of my work and share it like this. But I can imagine that it's not easy for a person who is trying to help me to correct any error in my calculations or to point out a certain fragment or equation from the screenshot. What can I do to make it little easier and convenient for others? The software can produce xHTML page too but the forum doesn't support the format. When I try to copy the latex code for the linked screenshot, I get the following which doesn't make much sense and I don't know how to put into proper latex form so it can be made work here.
Code:
038<p type="texpara" tag="Body Text" >$\U{394} P=\frac{8\U{3bc} LQ}{\U{3c0} R\U{2074} }$
038<p type="texpara" tag="Body Text" >$\U{394} P$ is the pressure difference between the two ends
038<p type="texpara" tag="Body Text" >$L$ is the length of pipe, $1$ $km$
038<p type="texpara" tag="Body Text" >$\U{3bc} $ is the dynamic viscosity, $8.90\times 10^{-4}$ $Pa$\textperiodcentered $s$
038<p type="texpara" tag="Body Text" >$Q$ is the volumetric flow rate, $2m^{3}/s$
038<p type="texpara" tag="Body Text" >$R$ is the pipe radius, $0.2m$
038<p type="texpara" tag="Body Text" >
038<p type="texpara" tag="Body Text" >$\U{394} P=\frac{8\U{3bc} LQ}{\U{3c0} R\U{2074} }=\frac{8\ast 8.90\times 10^{-4}\ast 997.6\ast 2}{\U{3c0} \ast 0.2^{4}}=\allowbreak \frac{8878.\,\allowbreak 6}{\U{3c0} }=2826$ $Pa$
Please let me know that how I can make it little easier for others. Thank you.