Shell Method Help - 24pi(-2/5y^2+7/5y^3-y^4)dy

In summary, the shell method is a mathematical technique used to calculate the volume of a solid of revolution. It differs from the disk method in that it uses cylindrical shells instead of circular disks and is typically used when the cross-sections of the solid are parallel to the axis of rotation. The general equation for the shell method is V = ∫2πrh dx, and it is used by determining the limits of integration, finding the radius and height of each shell, and then integrating the shell formula. An example of using the shell method is finding the volume of a solid formed by rotating the curve y = 2x^2 + 3 around the x-axis from x = 0 to x = 2, which can be calculated
  • #1
dakar76
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0

Homework Statement


X=12(y^2-y^3) Rotation is around y=-2/5


Homework Equations


V=2pi from the integral of a to b (shellradius)(shell height) dx


The Attempt at a Solution


2pi (-2/5+y)(12)(y^2-Y^3)dy
24pi (-2/5+y)(y^2-y^3)dy
24pi (-2/5y^2+7/5y^3-y^4)dy
24pi (-8/60y^2+21/60y^4-12/60y^5)
answer i get is 2/5pi when i integrat from 0 to 1 the book answer is 2pi
 
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  • #2
Please post the entire problem statement. Is the region being rotated bounded by some line, such as the y-axis?
 

FAQ: Shell Method Help - 24pi(-2/5y^2+7/5y^3-y^4)dy

What is the shell method used for?

The shell method is a mathematical technique used to calculate the volume of a solid of revolution, where the cross-sections of the solid are not perpendicular to the axis of rotation.

How is the shell method different from the disk method?

The shell method uses cylindrical shells to calculate the volume of the solid, while the disk method uses circular disks. The shell method is typically used when the cross-sections of the solid are parallel to the axis of rotation, while the disk method is used when the cross-sections are perpendicular.

What is the equation for the shell method?

The general equation for the shell method is V = ∫2πrh dx, where r is the distance from the axis of rotation to the shell, h is the height of the shell, and dx is the small change in the x-direction.

How do you use the shell method to find the volume of a solid?

To use the shell method, you first need to determine the limits of integration, which are the values of x that define the region of revolution. Then, you need to find the radius and height of each shell at a given x-value. Finally, you integrate the shell formula ∫2πrh dx from the lower limit to the upper limit to find the volume of the solid.

Can you provide an example of using the shell method to find the volume of a solid?

For example, if we have a solid of revolution formed by rotating the curve y = 2x^2 + 3 around the x-axis from x = 0 to x = 2, we can use the shell method to find its volume. The limits of integration are 0 and 2, and the radius of each shell is x, while the height is given by the function 2x^2 + 3. The volume can be calculated as V = ∫2πx(2x^2 + 3) dx from x = 0 to x = 2, which simplifies to V = 64π/5 units^3.

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