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1. A 41g object is attached to a horizontal spring with a spring constant of 15N/m and released from rest with an amplitude of 22.4cm. What is the velocity of the object when it is halfway to the equilibrium position if the surface is frictionless? Answer in units of m/s.
W=Square Root of (K/m)
1m=100cm
V^2+(wx)^2=(wA)^2
w= omega
A= Amplitude
K= 15N/m
m= 41kg
A=22.4cm=0.224m
W=sq root of K/m = 0.605
V^2=(wA)^2
V = 0.0677
Homework Equations
W=Square Root of (K/m)
1m=100cm
V^2+(wx)^2=(wA)^2
w= omega
A= Amplitude
The Attempt at a Solution
K= 15N/m
m= 41kg
A=22.4cm=0.224m
W=sq root of K/m = 0.605
V^2=(wA)^2
V = 0.0677
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