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Two charges create an electric field--electric field strenght at a point above h.fiel
Two charges are located on a horizontal axis. The Coulomb constant is 8.98755x10^9 Nm^2/C^2.
a) Determine the electric field at p on a vertical axis as shown in the attachment. Up is the positive direction. Answer in units of V/m.
b) Calculate the vertical component of the electric force on a -3.1e-6C charge placed at point p. Answer in units of N
a) E=kQ/r^2
b) F=Eq
a) I'm fairly certain I know how to find the field strength from the two charged particles, if point p was directly on the field and in the center.
E=E1+E2
E=k/r^2(Q+q)
E=8.98755e9/3^2(2.2e-6+2.2e-6)
E=4393 V/m
But I think I also need to take into account that p is above the two particles, but now I'm stuck...
b) I think this part would be easier, I just can't do it since I haven't gotten the answer to part a.
F=Eq
F=E(that would be found in part a)(-3.1e-6)
Homework Statement
Two charges are located on a horizontal axis. The Coulomb constant is 8.98755x10^9 Nm^2/C^2.
a) Determine the electric field at p on a vertical axis as shown in the attachment. Up is the positive direction. Answer in units of V/m.
b) Calculate the vertical component of the electric force on a -3.1e-6C charge placed at point p. Answer in units of N
Homework Equations
a) E=kQ/r^2
b) F=Eq
The Attempt at a Solution
a) I'm fairly certain I know how to find the field strength from the two charged particles, if point p was directly on the field and in the center.
E=E1+E2
E=k/r^2(Q+q)
E=8.98755e9/3^2(2.2e-6+2.2e-6)
E=4393 V/m
But I think I also need to take into account that p is above the two particles, but now I'm stuck...
b) I think this part would be easier, I just can't do it since I haven't gotten the answer to part a.
F=Eq
F=E(that would be found in part a)(-3.1e-6)