Should Integration by Parts Be Used on Functions Like \( x \cdot y(x) \)?

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In summary: Both of these integrals require integration by parts since the function being integrated cannot be expressed as a simple power of x. In summary, integration by parts is a technique used to integrate functions that cannot be integrated using the reverse power rule alone. It involves breaking down the integral into smaller parts and using the product rule to find the antiderivative.
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Fluidman117
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Homework Statement



I want to take an antiderivative of a function with respect to x. But in addition the function includes a term y (x) that is a function of x itself. Do I have to apply the reverse power rule also to y(x) also? The integral can be seen as an indefinite.

Homework Equations



[itex]A=\int x*y(x)*dx[/itex]

The Attempt at a Solution



I think I should just apply the reverse power rule to x. So:

[itex]A= \frac{x^{2}}{2}*y(x) + C [/itex]
 
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  • #2
Fluidman117 said:

Homework Statement



I want to take an antiderivative of a function with respect to x. But in addition the function includes a term y (x) that is a function of x itself. Do I have to apply the reverse power rule also to y(x) also? The integral can be seen as an indefinite.

Homework Equations



[itex]A=\int x*y(x)*dx[/itex]

The Attempt at a Solution



I think I should just apply the reverse power rule to x. So:

[itex]A= \frac{x^{2}}{2}*y(x) + C [/itex]

You can answer your own question---and that is the best way to learn! Just try it out on some examples. What do you get if you use your formula on the function ##y(x) = x^2##? What happens if you use your formula on ##y(x) = 1/x^2##? Are you getting correct results?
 
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  • #3
What you are looking for is something called integration by parts.
 
  • #4
Okay, then I believe I was mistaken. It seems that I also need to apply the reverse power rule to ##y(x)##.
So an example:
##y(x)=2*x##

[itex]A=\int^{2}_{1} x*y(x)*dx=\int^{2}_{1} x*2*x*dx[/itex]
[itex]A=\left|2\frac{x^{3}}{3}\right|^{2}_{1}=4.6667[/itex]

Is this correct?

I also looked up the integration by parts and it seems that in the above example it was possible to do without the integration by parts. But can someone give a good example why and when is it necessary to turn to the integration by parts technique?
 
  • #5
Fluidman117 said:
But can someone give a good example why and when is it necessary to turn to the integration by parts technique?

Try [itex]\displaystyle\int_0^\pi x \sin x\,dx[/itex] or [itex]\displaystyle\int_0^1 x e^{-x}\,dx[/itex].
 

FAQ: Should Integration by Parts Be Used on Functions Like \( x \cdot y(x) \)?

What is integration?

Integration is a mathematical process of finding the area under a curve. It involves finding the antiderivative of a function and evaluating it at two points to determine the area.

Why is integration important?

Integration is important in many areas of mathematics and science, as it allows us to solve a wide range of problems involving rates of change, motion, and accumulation. It also has practical applications in fields such as physics, engineering, and economics.

What are the different types of integration?

The two main types of integration are definite and indefinite. Definite integration involves finding the area under a curve between two specific points, while indefinite integration involves finding the antiderivative of a function without specifying any bounds.

How is integration related to differentiation?

Integration and differentiation are inverse operations of each other. Differentiation involves finding the rate of change of a function, while integration involves finding the accumulation of a function. They are connected through the fundamental theorem of calculus.

What are some common techniques for solving integration problems?

There are several techniques for solving integration problems, including substitution, integration by parts, trigonometric substitution, and partial fractions. It is important to choose the right technique based on the form of the function being integrated.

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