- #1
kwangiyu
- 2
- 0
Homework Statement
show that
[tex]\lim_{n->\infty} \frac{n^2}{2^n} = 0 [/tex]
Homework Equations
squeeze theorem
The Attempt at a Solution
I tried to use squeez theorem. I don't know how to do it because don't know how to reduce [itex]2^n[/itex]
However, I can solve this question like this.
Given [itex]\epsilon>0[/itex], find [itex]M \in N[/itex] such that [itex] M > max (4, \frac{1}{\epsilon}) [/itex] [itex]\mid \frac{n^2}{2^n} \mid = \frac{n^2}{2^n} < \frac{n}{n^2} = \frac{1}{n} < \frac{1}{M} <\epsilon[/itex]
[itex]2^n > n^2[/itex] and [itex]if x>4 [/itex]My question is how can I solve this problem with squeez theorem ?
Last edited by a moderator: