- #1
Zinggy
- 12
- 0
- Homework Statement
- Show directly by using the wave function in the Schrodinger equation, that this equation satisfies the Schrödinger equation
- Relevant Equations
- V(x)=1/2kx^2
E=(5ħ/2)√(k/m)
α=(mk/ħ)^1/4
Ψ(x,t) =ψ (x)φ (t) = √(α)/[2√(2π^1/4)]*e^((-1/2)α^2x^2)[-2+α^2 x^2]e^(-iEt/ħ)
I apologize for the bad formatting:
To start off, I'm trying to use the Schrodinger Equation in the form: (ħ/2m) d^2Ψ(x,t)/dx^2+V(x,t)Ψ(x,t)=EΨ(x,t)
I couldn't remember if I need to also take the partial derivative with respect to T as well, but I started off with just X.
I plugged in my known values into the equation which gives me the very messy:
(ħ/2m)d^2[√(α)/[2√(2π^1/4)]*e^((-1/2)α^2x^2)[-2+α^2 x^2]e^(-iEt/ħ)]/dx^2 +(1/2kx^2)(√(α)/[2√(2π^1/4)]*e^((-1/2)α^2x^2)[-2+α^2 x^2]e^(-iEt/ħ)) = (5ħ/2)√(k/m)* √(α)/[2√(2π^1/4)]*e^((-1/2)α^2x^2)[-2+α^2 x^2]e^(-iEt/ħ)
This already seemed wrong to me, but I carried on and tried to take the second derivative with respect to X and got the following:
√(α)/[2√(2π^1/4)]*α^2 e^[-1/2(α^2 x^2)] (α^2 x^2 -1) [-2+8α^2)e^[-iEt/ħ] = d^2Ψ(x,t)/dx^2
From here I extracted common terms, giving me:
√(α)/[2√(2π^1/4)] * e^[-iEt/ħ]*e^[-1/2(α^2 x^2)] * {(ħ/2m)α^2(α^2 x^2 -1)[-2+8α^2)+1/2kx^2[-2+4α^2x^2]} = EΨ(x,t)
From this point I divided both sides by √(α)/[2√(2π^1/4)] and e^[-1/2(α^2 x^2)] giving me
e^[-iEt/ħ]* {(ħ/2m)α^2(α^2 x^2 -1)[-2+8α^2)+1/2kx^2[-2+4α^2x^2]} = E([-2+α^2 x^2]e^(-iEt/ħ)]
After this point I don't really know where to go. I don't understand how to isolate and solve for either ψ(x) or φ (t), I also don't know if I should've also taken the second derivative with respect to T as well.
I appreciate any time and Input. Thanks.