Showing that KE is minimized when objects stick together in a collision

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In summary, the problem involves an inelastic collision between two masses, where Mass A has an initial velocity and collides with Mass B which is initially at rest. The kinetic energy of the system after the collision is given by the equation K_f = (1/2)m_A(V_Ax^2 + V_Ay^2) + (1/2)m_B(V_Bx^2 + V_By^2). To show that this quantity is minimized when the objects stick together, the derivative is taken with respect to one of the four velocity variables. The x and y directions are shown to be independent, and momentum is used to make a substitution in the derivative. Taking the second derivative shows that the concavity should be negative,
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Homework Statement



This problem deals with an inelastic collision, where Mass A is given an initial velocity and collides with Mass B which is initially at rest.

The equation I'm given is

[itex]K_f = \frac{1}{2} m_A (V_Ax^2 + V_Ay^2) + \frac{1}{2} m_B (V_Bx^2 + V_By^2)[/itex]
The x's and y's are part of the subscript.

So the problem says:

Start with the expression shown above for the system's kinetic energy after the collision. Energy is not a vector, but the final total speeds are expressed with x and y components, by Pythagorean theorem. This notation puts them on a comparable footing with momentum, which is a vector.

Show that this quantity is minimized when the objects stick together.

The following steps will walk you through it:

a) Take the derivative with respect to anyone of the four velocity variables (your choice).

b) The x and y directions are independent, i.e. if you pick an x variable, the derivatives of the y variables are 0.

c) The two variables along the same axis are NOT independent. Use momentum to make a substitution. This should lead to some clear conclusions.

d) Now take the 2nd derivative to get the concavity. What sign should it be?

e) Without recomputing, extrapolate what you would have gotten if you had chosen a variable from the other axis in step a (y instead of x, etc.). Why is this step necessary to demonstrate that the objects truly do "stick together"? The attempt at a solution

So for part a, I chose to take the derivative with respect to Vax and I get
dk/dVa = [itex]m_A V_A + m_B V_B (dV_B/dV_A) [/itex]

Now I'm really lost on part c. I'm really unclear as to how to use momentum and what to substitute in.
 
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Azu_ said:
I'm really unclear as to how to use momentum and what to substitute in.
Momentum is a conserved vector, so it is conserved in each of the directions, x and y, separately. Write down two equations expressing this.
 

FAQ: Showing that KE is minimized when objects stick together in a collision

How is kinetic energy related to objects sticking together in a collision?

When objects stick together in a collision, kinetic energy is minimized. This means that the total amount of kinetic energy before the collision is greater than the total amount of kinetic energy after the collision.

What is the concept of conservation of momentum and how does it relate to minimizing kinetic energy?

Conservation of momentum states that in a closed system, the total momentum before a collision is equal to the total momentum after the collision. When objects stick together in a collision, the total momentum after the collision is equal to the total momentum before the collision. This means that the objects have a lower velocity after the collision, resulting in a lower kinetic energy.

How does the coefficient of restitution affect the minimization of kinetic energy?

The coefficient of restitution is a measure of how much kinetic energy is lost during a collision. A coefficient of restitution of 0 means that all kinetic energy is lost and the objects stick together, while a coefficient of restitution of 1 means that no kinetic energy is lost and the objects bounce off each other. Therefore, a lower coefficient of restitution results in a lower kinetic energy after the collision.

Can you provide an example of a real-life scenario where objects sticking together in a collision result in a minimized kinetic energy?

A common example is a car crash. When two cars collide and stick together, the kinetic energy of the cars is minimized. This is why it is safer to have a car with airbags and crumple zones, as they help to increase the time of impact and reduce the force of the collision, resulting in a lower kinetic energy and less damage to the passengers.

Are there any exceptions to the concept that kinetic energy is minimized when objects stick together in a collision?

In elastic collisions, where no kinetic energy is lost, the objects will not stick together and the kinetic energy will not be minimized. This can occur with objects with a high coefficient of restitution or in highly elastic materials, such as rubber.

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