- #1
freydawg56
- 22
- 0
I know that y(t) = t x(t) is unstable, for bounded inputs yielding unbounded outputs, but would
y(t) = x(t)/ t also be unstable? when t is going in the negative direction? please help. test Monday.
y(t) = x(t)/ t also be unstable? when t is going in the negative direction? please help. test Monday.