- #1
kostoglotov
- 234
- 6
Homework Statement
Two pieces of copper weighing 10 grams each are 10 cm apart and 1/1000 electrons are transferred from one to the other. Find the force of electrostatic attraction between them.
Homework Equations
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Molar mass Cu: 63.5 g/mol
[tex] \frac{1}{4\pi \epsilon_0} = 9 \times 10^9 [/tex]
##e = 1.6 \times 10^{-19} \ C##
Avagadro: ##6 \times 10^{23}##
The Attempt at a Solution
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Actually, I only have one minor thing I don't understand.
In my solution I have
[tex] F = 9 \times 10^9 \frac{-15.12 \times +15.12}{0.1^2} [/tex]
Whereas the solution outlined in the book only uses one charge in the numerator
[tex] F = 9 \times 10^9 \frac{15.12}{0.1^2} [/tex]
So my answer is out by a factor of 15.12.
I don't get it. Wouldn't the charge on one of the copper pieces be +15.12 C and the other -15.12 C and therefore q1 x q2 would equal ##- 15.12^2##...?