Simple Calculus Question: Differentiating Square Root Fraction

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In summary, The problem is to differentiate the expression, \sqrt{\frac{1-cos2x}{1+cos2x}}, with respect to x. The attempt at a solution involves simplifying the expression and arriving at the correct answer of sec2x. However, the textbook also includes the term tanx/|tanx| in the answer, but it is not necessary as it simplifies to sec2x. The only reason for specifying this term could be to account for taking the square root of the radical.
  • #1
nil1996
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Homework Statement



[itex]\sqrt{\frac{1-cos2x}{1+cos2x}}[/itex]
differentiate with respect to x

Homework Equations



none

The Attempt at a Solution



i have simplified it by substituting cos2x as 1-2sin2x and 2cos2x-1

I have got the answer as sec2x but my textbook says the ans is [itex]\frac{tanx}{|tanx|}[/itex]sec2x
why??

please help
 
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  • #2
Your answer is correct. I don't see the need for your book to specify tanx/tanx in it.
 
  • #3
rock.freak667 said:
I don't see the need for your book to specify tanx/tanx in it.

it is tanx/|tanx|
the denominator is mod of tanx
 
  • #4
nil1996 said:
it is tanx/|tanx|
the denominator is mod of tanx

Yes well the main point was that for x>0, |tanx| = tanx so it would cancel out to give you sec2x.

The only reason I can think of to specify something like that is if you accounted for taking the square root of the radical.

Meaning that your expression would simplify to √(tan2x) = ± tanx

and d/dx(± tanx) = ± sec2x
 
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  • #5
thanks got it
 

FAQ: Simple Calculus Question: Differentiating Square Root Fraction

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