- #1
Dumbledore
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Homework Statement
What is the time rate of change of height after 5.0s?
Homework Equations
theta = 3t/(2t + 10)
adjacent length = 1000
Therefore: opposite length (height) h = 1000 tan (3t/(2t+10))
The Attempt at a Solution
I thought it would be simply finding the derivative of the second equation (dh/dt) and plugging in 5 for t.
dh/dt = 1000 * ( sec(3t/(2t+10)) )^2 * [ (2t+10)*3 - 3t(2)/ (2t + 10)^2 ]
dh/dt |t=5 = 1000/(cos.75)^2 * 3/40
= 75.01...
75 m/s
Is this not correct?