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Shafty
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This problem seems simple enough, yet my professor says my answer is incorrect. Here is the problem.
1 ml of a 0.10 M solution of HCL is added to 21 ml of distilled water. What is the final concentration of the solution (M)?
Im going to use the equation
C1*V1=C2*V2
Where C1 is the initial concentration (M) and C2 is the final Concentration, and V1 is initial Volume, and V2 is final volume
If I add 1ml of HCl to 21ml of H2O, I will have 22ml of solution. This is V2, therefore
C1V1/V2=C2
(0.1M)(1ml)/(22ml)=C2
C2= 0.0045 M
What am I overlooking?
Thanks in advance.
1 ml of a 0.10 M solution of HCL is added to 21 ml of distilled water. What is the final concentration of the solution (M)?
Im going to use the equation
C1*V1=C2*V2
Where C1 is the initial concentration (M) and C2 is the final Concentration, and V1 is initial Volume, and V2 is final volume
If I add 1ml of HCl to 21ml of H2O, I will have 22ml of solution. This is V2, therefore
C1V1/V2=C2
(0.1M)(1ml)/(22ml)=C2
C2= 0.0045 M
What am I overlooking?
Thanks in advance.