Simple displacement and acceleration question

In summary, the given equation represents position and the change in position over the change in time is velocity. The derivative of the given equation is used to find the velocity at any given point. The displacement and average velocity can be found by plugging in the values for t=0 and t=2. The displacement is -2 and the average velocity is -1.
  • #1
jaydnul
558
15

Homework Statement



Find the body's displacement and average velocity for the given time interval.

s=t^2 -3t +2, 0<=t<=2


Homework Equations



d(displacement)/d(time) is for the acceleration right?


The Attempt at a Solution



So here is my problem. I got 2t-3 for the derivative, but i don't really know how to apply it to the question. I feel like i need just one value for t in order to find the displacement and velocity at that point, right? So how do i incorporate a full interval, 0 to 2? The back of the book says -2 for displacement and -1 for acceleration, but i have no clue how that is the case when you have multiple values of t. I would have just said the 2t-3.
 
Physics news on Phys.org
  • #2
What does the given equation represent? Position? Velocity? Acceleration?

The change in POSITION(not displacement, they are related but not the same) over the change in time is velocity. the change in velocity over the change in time is accleration.

d(POSITION)/d(time) is not acceleration. When you get confused on these, try and just think about the units you would be working with it. X(meters) over T(seconds) That is m/s which is velocity. I think you are getting position and displacement confused. Position is simply where something is at any given time. Where as the displacement is Δx or the change in its position. Additionally, you are dealing with the CHANGE in time. That being said, yes. It is necessary to have more than one value for t.
 
Last edited:
  • #3
lundyjb said:
So here is my problem. I got 2t-3 for the derivative, but i don't really know how to apply it to the question. I feel like i need just one value for t in order to find the displacement and velocity at that point, right? So how do i incorporate a full interval, 0 to 2? The back of the book says -2 for displacement and -1 for acceleration, but i have no clue how that is the case when you have multiple values of t. I would have just said the 2t-3.
There's no need for calculus here. You are given the position (s) as a function of time.

What's the definition of displacement?

What's the definition of average velocity? (They want velocity, not acceleration.)
 
  • #4
What is s(t) when t = 0? What is s(t) when t = 2?
 
  • #5


As a scientist, it is important to understand the concepts of displacement and acceleration in order to accurately solve problems like this. In this case, the body's displacement and average velocity can be found by taking the derivative of the given equation, s=t^2 -3t +2, with respect to time. This will give us the velocity equation, v=2t-3.

To find the average velocity, we need to take the integral of the velocity equation over the given time interval, 0 to 2. This will give us the displacement equation, d= t^2 -3t +2. Plugging in the values of 0 and 2 into this equation, we get a displacement of -2, which is the same value given in the back of the book.

As for the average velocity, we can use the formula v_avg= (d_final - d_initial)/t_final - t_initial. Plugging in the values of -2 for d_final, 0 for d_initial, 2 for t_final and 0 for t_initial, we get an average velocity of -1. This is also the same value given in the back of the book.

In conclusion, it is important to understand the concepts of displacement and velocity in order to solve problems like this. By taking the derivative and integral, we can accurately find the displacement and average velocity for the given time interval.
 

FAQ: Simple displacement and acceleration question

What is simple displacement and acceleration?

Simple displacement and acceleration are two fundamental concepts in physics that describe the motion of an object. Displacement refers to the change in an object's position from its starting point, while acceleration refers to the rate at which an object's velocity changes.

How is displacement calculated?

Displacement can be calculated by subtracting the initial position of an object from its final position. It is represented by the symbol Δx (delta x) and is measured in units of length, such as meters or kilometers.

What is the difference between displacement and distance?

Displacement and distance are often used interchangeably, but they have different meanings. Distance refers to the total length of the path traveled by an object, while displacement only considers the change in an object's position from its starting point.

How is acceleration measured?

Acceleration is measured in units of distance per time squared, such as meters per second squared (m/s²) or kilometers per hour squared (km/h²). It can be calculated by dividing the change in velocity by the change in time.

What factors affect an object's displacement and acceleration?

An object's displacement and acceleration can be affected by various factors, including its initial velocity, the force acting on it, and the mass of the object. Other external factors such as friction and air resistance can also impact displacement and acceleration.

Back
Top