Simple drift speed probem driving me nuts

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The discussion revolves around calculating the drift speed of electrons in a silver wire with a current of 200 mA and a radius of 0.8 mm. The original poster calculates the drift speed and number density but arrives at a different answer than the textbook. They use the equations J = I/A and J = nev_d, but their calculations yield 1.06 x 10^-4 instead of the expected 1.07 x 10^-5. A participant points out that the error stems from using an incorrect value for the density of silver. The conversation highlights the importance of accurate constants in physics calculations.
ttran1117
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Homework Statement


A current of 200 mA flows in a silver wire of radius 0.8mm. Find (a) the drift speed of the electrons. (b) the number density of particles.

Homework Equations


The Attempt at a Solution


The answer in the book is 1.07 x 10^-5, but I'm getting 1.06 x 10^-4. Can anyone tell me what I'm doing wrong?

So, I have J = I/A and J=nev_d ==> v_d = J/(ne)
J = 200 x 10^-3/pi(0.8x10^-3)^2

n = p*Avg/M
= 1.05 * 6.022 x 10^23 / 107.868 x 10^-3

plugging in for v_d, I get 1.06 x 10^-4.

This problem is supposed to be simple, but it's driving me nuts! Someone help please! Thanks a lot
 
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You used wrong value for the density of silver.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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