- #1
Peter G.
- 442
- 0
Hi,
9 (a) Write down an equation for the displacement of a particle undergoing SHM with an amplitude equal to 8.0 cm and a frequency of 14 Hz, assuming that at t = 0 displacement is = to 8.0 cm and the particle is at rest.
What I got (and this agrees with the book) was: x = 8.0 cos (28pi*t)
The problem is the book then asks for the displacement, velocity and acceleration at 0.025 seconds.
I simply plugged in the numbers for the displacement and got the -4.7 cm the book gets as well. My answers for the acceleration and velocity however, do not agree with the book. Can anyone help me spot my errors?
a = -ω2x
a = -(28pi)2x(-0.047)
I get around 36 while the book gets 360.
But, the difference in our velocity results is more significant:
v= ±ω√(xo2-x2)
v =±(28pi) √(0.082 + 0.0472)
The book gets negative -5.7ms while I get positive or negative 8.16
Thanks,
Peter G.
9 (a) Write down an equation for the displacement of a particle undergoing SHM with an amplitude equal to 8.0 cm and a frequency of 14 Hz, assuming that at t = 0 displacement is = to 8.0 cm and the particle is at rest.
What I got (and this agrees with the book) was: x = 8.0 cos (28pi*t)
The problem is the book then asks for the displacement, velocity and acceleration at 0.025 seconds.
I simply plugged in the numbers for the displacement and got the -4.7 cm the book gets as well. My answers for the acceleration and velocity however, do not agree with the book. Can anyone help me spot my errors?
a = -ω2x
a = -(28pi)2x(-0.047)
I get around 36 while the book gets 360.
But, the difference in our velocity results is more significant:
v= ±ω√(xo2-x2)
v =±(28pi) √(0.082 + 0.0472)
The book gets negative -5.7ms while I get positive or negative 8.16
Thanks,
Peter G.