Simple Harmonic Motion - Getting Acceleration from Velocity

In summary, the student is conducting an experiment to measure the force exerted by a speaker driven by a known voltage and frequency. They are assuming that the speaker undergoes simple harmonic motion (SHM) and are measuring its peak to peak velocity. They are trying to determine the amplitude (A) in their equations and are questioning whether the amplitude refers to the voltage or displacement of the speaker. They also consider an alternative approach for calculating the acceleration.
  • #1
jasonian
1
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Homework Statement


I am doing an experiment where I am measuring the force a speaker is exerting when it is driven by a certain voltage and frequency, so my voltage and frequency values are known. I am assuming the speaker is undergoing SHM and I am measuring its peak to peak velocity.

Homework Equations


I understand that for SHM:

x = Asin(wt)
x' = wAcos(wt)
x'' = -w^2Asin(wt)

The Attempt at a Solution


Now, because I am measuring the peak to peak velocity, is it correct to say cos(wt) and sin(wt) are equal and therefore x'' = -w*x', where w = 2*pi*f and x' = my peak to peak velocity measurements divided by 2.

Furthermore, if I were not to take this approach my acceleration equation would be x'' = -w^2Asin(wt).
Where,

w = 2*pi*f
t = period of 1 cycle
A = (?)

I am not quite sure what the amplitude would be in my situation. What kind of amplitude is required? The amplitude of the voltage driving the speaker? Or the amplitude of the displacement of the speaker? (Which in this case is unknown as only the velocity measurements are taken).

Any help is appreciated. Thanks.
 
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  • #2
jasonian said:

Homework Statement


I am doing an experiment where I am measuring the force a speaker is exerting when it is driven by a certain voltage and frequency, so my voltage and frequency values are known. I am assuming the speaker is undergoing SHM and I am measuring its peak to peak velocity.

Homework Equations


I understand that for SHM:

x = Asin(wt)
x' = wAcos(wt)
x'' = -w^2Asin(wt)

The Attempt at a Solution


Now, because I am measuring the peak to peak velocity, is it correct to say cos(wt) and sin(wt) are equal and therefore x'' = -w*x', where w = 2*pi*f and x' = my peak to peak velocity measurements divided by 2.

Furthermore, if I were not to take this approach my acceleration equation would be x'' = -w^2Asin(wt).
Where,

w = 2*pi*f
t = period of 1 cycle
A = (?)

I am not quite sure what the amplitude would be in my situation. What kind of amplitude is required? The amplitude of the voltage driving the speaker? Or the amplitude of the displacement of the speaker? (Which in this case is unknown as only the velocity measurements are taken).

Any help is appreciated. Thanks.

Look at graphs of ##\sin(\theta)## and ##\cos(\theta)##; you will see that where one of them is at a peak the other is half-way between a peak and a through; that is, when ##\sin(\theta) = \pm 1## we have ##\cos(\theta) = 0##, and vice-versa. You can also see this without drawing a graph if you remember that ##\sin^2(\theta) + \cos^2(\theta) = 1## for all angles ##\theta##.
 

FAQ: Simple Harmonic Motion - Getting Acceleration from Velocity

What is Simple Harmonic Motion?

Simple Harmonic Motion is a type of periodic motion in which an object oscillates back and forth around a central equilibrium position, with the motion being governed by a restoring force that is proportional to the displacement from the equilibrium position.

How is Simple Harmonic Motion mathematically represented?

The mathematical representation of Simple Harmonic Motion is given by the equation a = -ω^2x, where a is the acceleration, x is the displacement from the equilibrium position, and ω is the angular frequency of the motion.

How can acceleration be calculated from velocity in Simple Harmonic Motion?

The acceleration in Simple Harmonic Motion can be calculated by taking the derivative of the velocity equation, which is v = ω√(A^2 - x^2), where v is the velocity, A is the amplitude of the motion, and x is the displacement from the equilibrium position. The resulting equation for acceleration is a = -ω^2x.

What is the relationship between acceleration and velocity in Simple Harmonic Motion?

The relationship between acceleration and velocity in Simple Harmonic Motion is that acceleration is directly proportional to the displacement from the equilibrium position and inversely proportional to the square of the angular frequency. This means that as the displacement increases, the acceleration also increases, while a larger angular frequency leads to a smaller acceleration.

What are some real-life examples of Simple Harmonic Motion?

Some common examples of Simple Harmonic Motion in everyday life include the motion of a pendulum, the vibrations of a guitar string, and the movement of a mass on a spring. Other examples include the bobbing of a buoy in water, the swinging of a door, and the bouncing of a trampoline.

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