Simple Harmonic Motion (Pendulum)

In summary, the period of oscillation of the pendulum with a bob of mass 0.050kg is 1.00s, while the period of oscillation of the pendulum with a mass of 0.100kg is 2.01s.
  • #1
KMcFadden
28
0

Homework Statement


Two pendula of length 1.00m are set in motion at the same time. One pendula has a bob of mass 0.050kg and the other has a mass of 0.100kg.

1. What is the ratio of the periods of oscillation?

2. What is the period of oscillation if the initial angular displacement is small?

3. What is the period of oscillation if the initial angular displacement is 60.0°? Calculate the series out to three terms.


Homework Equations



1. T=2π√(L/g)

2. T=2π√(L/g)[1+1^2/2^2 〖sin〗^2 (θ/2)+(1^2 3^2)/(2^2 4^2 ) 〖sin〗^4 (θ/2)+(1^2 3^2 5^2)/(2^2 4^2 6^2 ) 〖sin〗^6 (θ/2)]

The Attempt at a Solution



1. 1:2 or 2:1 depending on which you consider mass 1 or mass 2.

2. T=2π√(L/g)
T=2π√(1.00m/〖9.808m/s〗^2 )
T=2.01s

3. T=2π√(L/g)[1+1^2/2^2 〖sin〗^2 (θ/2)+(1^2 3^2)/(2^2 4^2 ) 〖sin〗^4 (θ/2)+(1^2 3^2 5^2)/(2^2 4^2 6^2 ) 〖sin〗^6 (θ/2)]

T=2π√(1.00m/〖9.808m/s〗^2 )[1+1^2/2^2 〖sin〗^2 (60/2)+(1^2 3^2)/(2^2 4^2 ) 〖sin〗^4 (60/2)+(1^2 3^2 5^2)/(2^2 4^2 6^2 ) 〖sin〗^6 (60/2)]

T=2.006[1+0.5000+0.0088+0.00153]

T=2.006[1.51033]

T=3.03s
 
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  • #2
Are my solutions correct?
 
  • #3
KMcFadden said:

Homework Statement


Two pendula of length 1.00m are set in motion at the same time. One pendula has a bob of mass 0.050kg and the other has a mass of 0.100kg.

1. What is the ratio of the periods of oscillation?

2. What is the period of oscillation if the initial angular displacement is small?

3. What is the period of oscillation if the initial angular displacement is 60.0°? Calculate the series out to three terms.


Homework Equations



1. T=2π√(L/g)

2. T=2π√(L/g)[1+1^2/2^2 〖sin〗^2 (θ/2)+(1^2 3^2)/(2^2 4^2 ) 〖sin〗^4 (θ/2)+(1^2 3^2 5^2)/(2^2 4^2 6^2 ) 〖sin〗^6 (θ/2)]

The Attempt at a Solution



1. 1:2 or 2:1 depending on which you consider mass 1 or mass 2.

Is m included in the formula for T?

2. T=2π√(L/g)
T=2π√(1.00m/〖9.808m/s〗^2 )
T=2.01s

3. T=2π√(L/g)[1+1^2/2^2 〖sin〗^2 (θ/2)+(1^2 3^2)/(2^2 4^2 ) 〖sin〗^4 (θ/2)+(1^2 3^2 5^2)/(2^2 4^2 6^2 ) 〖sin〗^6 (θ/2)]

How is this formula derived? Where did you get it?
 
  • #4
You should revise your concepts
 
  • #5
The formulas used were those provided by my lab manual.
 
  • #6
OK, let's start with part 1. Your formula is correct. So where do you get the idea that T is a function of mass?

In part 2, I realize you were given that formula. I probably should not have commented at all, but what I had in mind is that you're being given a formula without its prior derivation, and no way could you have been shown its derivation. So, bottom line, never mind on part 2.
 

Related to Simple Harmonic Motion (Pendulum)

1. What is Simple Harmonic Motion (Pendulum)?

Simple Harmonic Motion (Pendulum) is a type of periodic motion in which an object oscillates back and forth around a central equilibrium point due to the force of gravity. It follows a specific pattern and can be described by the relationship between the mass of the object, the length of the pendulum, and the acceleration due to gravity.

2. What factors affect the period of a pendulum?

The period of a pendulum is affected by the length of the pendulum, the mass of the object attached to the pendulum, and the acceleration due to gravity. The longer the pendulum, the longer the period. The heavier the object, the longer the period. And the stronger the force of gravity, the shorter the period.

3. How does the amplitude of a pendulum affect its motion?

The amplitude of a pendulum, which is the maximum displacement from the equilibrium point, does not affect the period of the pendulum. However, it does affect the maximum velocity and acceleration of the pendulum. A larger amplitude will result in a higher maximum velocity and acceleration, while a smaller amplitude will result in a lower maximum velocity and acceleration.

4. What is the relationship between the length of a pendulum and its period?

The length of a pendulum and its period have an inverse relationship. This means that as the length of the pendulum increases, the period also increases. This relationship can be described by the equation T=2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

5. How does the angle of displacement affect the motion of a pendulum?

The angle of displacement, or the initial angle at which the pendulum is released, does not affect the period of the pendulum. However, it does affect the path of the pendulum and the amount of potential and kinetic energy it has. A larger initial angle will result in a higher potential energy and a lower kinetic energy, while a smaller initial angle will result in a lower potential energy and a higher kinetic energy.

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