- #1
badtwistoffate
- 81
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just started ordinary differential equation class, and i have to find the general soln of the eqn: y'=y(3-y)... just started so i only know of the method of separation of varibles.
Thought of multiplying the y through so it becomes:
y'=3y-y^2 then do..
dy/dx=3y-y^2 then... I am stuck... I tried doing separation of varibles by
Dividing 3y-y^2 to the other side so you get:
dy/3y-y^2=0? But that doesn't seem right.
Thought of multiplying the y through so it becomes:
y'=3y-y^2 then do..
dy/dx=3y-y^2 then... I am stuck... I tried doing separation of varibles by
Dividing 3y-y^2 to the other side so you get:
dy/3y-y^2=0? But that doesn't seem right.
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